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goldenfox [79]
3 years ago
6

How many positive factors of 200 are divisible by 4?

Mathematics
1 answer:
Stella [2.4K]3 years ago
3 0

Answer:

C. 6, D. 20, B. 18, B. 9

Step-by-step explanation:

#1. Factors of 200 are 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100 & 200, of which 6 are divisible by 4 (4, 8, 20, 40, 100 & 200)

#2. Prime factors of 35 are 7 & 5, twice the sum of these factors, k = 24. k-4 = 20

#3. Non-multiples of 4 nor 5 between 16 and 45 are 17, 18, 19, 21, 22, 23, 26, 27, 29, 31, 33, 34, 37, 38, 39, 41, 42 & 43...thus 18 non-multiples

#4. Even factors of 120 greater than 1 and less than 40 are 2, 4, 6, 8, 10, 12, 20, 24 & 30...thus there are 9 even factors

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Answer:

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Step-by-step explanation:

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3 years ago
What is the additive inverse of x=-1317, and verify -(-x) = x ?
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Answer:

1317 is the additive inverse of x = -1317.

Step-by-step explanation:

Additive inverse of a number which when added to the original number gives zero as the result.

Additive inverse of x = -1317

-1317 + 1317 = 0

1317 is the additive inverse of x = -1317.

<u>Verification of -(-x) = x </u>

<u>L. H. S </u>

-(-x) = -{-(-1317)}

= - 1317

<u>R. H. S</u>

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2 years ago
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3 years ago
Write an equation for the
Travka [436]

Answer:

See below

Step-by-step explanation:

For the model function f(x)=a|x-h|+k, (h,k) is the vertex, and a is the horizontal growth or shrink factor.

We know that our vertex is (-1.5,0) from our graph, so we'll need to determine the value of a by using one of the points on the graph:

f(x)=a|x-h|+k\\\\f(x)=a|x-(-1.5)|+0\\\\f(x)=a|x+1.5|\\\\f(0)=a|0+1.5|\\\\3=a|1.5|\\\\3=1.5a\\\\2=a

Thus, our equation for the given graph is f(x)=2|x+1.5|.

The domain of a function is the set of all existing real x-values, thus, our domain for the given function is (-\infty,\infty), or all real x-values.

The range of a function is the set of all existing real y-values, thus, our range for the given function is [-1,\infty), or all real y-values starting with y=-1 which is included.

8 0
2 years ago
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dusya [7]

Answer:

The coefficient in the first term is 4

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The variable in the third term is y

Step-by-step explanation:

The constant is 6 because it is the only term without a variable, therefore the one term that will stay the same/remain constant.

The first term is 4x^2, the second term is -5x, the third term is 3y, and the fourth term is 6.

The variable in the first term is x^2, therefore the coefficient of x^2 is 4.

8 0
3 years ago
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