1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yuradex [85]
3 years ago
13

-9 3/4 + 6 3/4 = what

Mathematics
1 answer:
murzikaleks [220]3 years ago
6 0
-3 .....//..:’dmnrnsndndndbdbbdbsbd need characters
You might be interested in
Which solution value satisfies the inequality equation x-5 s 14? Ox= 25 x = 21 x= 19 x = 20​
PolarNik [594]

Answer:

x = 19

Step-by-step explanation:

x-5 = 14\\

Collect like terms

x =14+5

Add ; 14+5 =19

x =19

6 0
3 years ago
Twelve times a number x, plus a second number y.
faust18 [17]

Answer:

12x+y

Step-by-step explanation:

12 times a number x

12x

Plus y

12x+y

3 0
3 years ago
Is 90 cm less than 9 mm
Alex Ar [27]
90 cm is greater than 9mm
6 0
3 years ago
Read 2 more answers
Multiply 13(4w -3) what is the answer
Sophie [7]
The answer would be 52w -39
4 0
3 years ago
Read 2 more answers
Please i’ll make u brainliest
Nikitich [7]
I think 35/70 is the answer
6 0
3 years ago
Other questions:
  • What is the equation for the line?<br><br><br><br> Enter your answer in the box.
    7·2 answers
  • Forty-two of the students in band own their instrument.
    7·1 answer
  • Geometry Math Homework (Pic Included)
    6·1 answer
  • Dough says that the opposite of -2/5 is 5/-2 is he correct
    14·2 answers
  • Someone please help, i’m so dumb
    6·1 answer
  • Write in radical form
    14·1 answer
  • HURRY MY QUIZ IS TIMED Which expression is equivalent to 4x-9+6y + 17x?
    5·2 answers
  • How is 400, 000 + 8000 + 500 + 6 written in standard form ?
    9·2 answers
  • WILL MARK BRAINLIEST!!!
    12·2 answers
  • Find the number of integral solutions of x+y +z = 12, where −3 ≤ x ≤ 4, 2 ≤ y ≤ 11, and<br> z ≥ 3.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!