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postnew [5]
3 years ago
5

2/3g + 1/2g = 14what is g?

Mathematics
2 answers:
miskamm [114]3 years ago
5 0

2/3 g + 1/2 g = 14

4/6 g + 3/6 g = 14

7/6 g = 14

7g = 84

g = 12

Step2247 [10]3 years ago
4 0

2/3g + 1/2g = 14

Add 2/3 and 1/2. Multiply 2/3 by 2/2 and 1/2 by 3/3 to make both fractions have common denominators.

  1. 2/3 * 2/2 = 4/6
  2. 1/2 * 3/3 = 3/6

4/6g + 3/6g = 14

  • Combine like terms.

7/6g = 14

  • Divide both sides by 7/6.

g = 14 ÷ 7/6

  • g = 14 × 6/7 = 84/7 = 12

g = 12

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Collin has 6 yards of fabric he will take 2/3 of a yard fabric how many aprons can he make.
Lena [83]

Answer:

9

Step-by-step explanation:

2/3 x 2 is 1, 1/3 another will make 2 aprons do that 3 more times and u will run out of fabric and will have 9 aprons

7 0
2 years ago
Read 2 more answers
A manufacturer wants to make open tin boxes from pieces of tin with dimensions 8 in. by 15 in. by cutting equal squares from the
Stells [14]

Answer:

\frac{5}{3} in

Step-by-step explanation:

Let x be the side of square.

Length of box=8-2x

Width of box=15-2x

Height of box=x

Volume of box=L\times B\times H

Substitute the values then we get

Volume of box=V(x)=(8-2x)(15-2x)x=(15x-2x^2)(8-2x)

V(x)=120x-30x^2-16x^2+4x^3

V(x)=4x^3-46x^2+120x

Differentiate w.r.t x

V'(x)=12x^2-92x+120

V'(x)=0

12x^2-92x+120=0

3x^2-23x+30=0

3x^2-18x-5x+30=0

3x(x-6)-5(x-6)=0

(x-6)(3x-5)=0

x-6=0\implies x=6

3x-5=0\implies x=\frac{5}{3}

Again differentiate w.r.t x

V''(x)=24x-92

Substitute x=6

V''(6)=24(6)-92=52>0

Substitute x=5/3

V''(5/3)=24(5/3)-92=-52

Hence, the volume is maximum at x=\frac{5}{3}

Therefore, the side of the square ,x=\frac{5}{3} in cutout that gives the box the largest possible volume.

5 0
3 years ago
HELP ASAPPPP!!! Question in pic. Find the value of x
erik [133]

Answer:

x = 14

Step-by-step explanation:

30 = 3x - 12 (vertically opp)

30 + 12 = 3x

42 = 3x

42÷3 = x

14 = x

5 0
2 years ago
Plz answer it’s easy giving brainliest
MariettaO [177]
What is the name of that type of math
5 0
3 years ago
A function of the form f(x)=ab^x is modified so that the b value remains the same but the a value is increased by 2. How do the
ANEK [815]

Answer:

The domain and range remain the same.

Step-by-step explanation:

Hi there!

First, we must determine what increasing <em>a</em> by 2 really does to the exponential function.

In f(x)=ab^x, <em>a</em> represents the initial value (y-intercept) of the function while <em>b</em> represents the common ratio for each consecutive value of f(x).

Increasing <em>a</em> by 2 means moving the y-intercept of the function up by 2. If the original function contained the point (0,x), the new function would contain the point (0,x+2).

The domain remains the same; it is still the set of all real x-values. This is true for any exponential function, regardless of any transformations.

The range remains the same as well; for the original function, it would have been y\neq 0. Because increasing <em>a</em> by 2 does not move the entire function up or down, the range remains the same.

I hope this helps!

3 0
2 years ago
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