This is a combination problem.
Given:
12 students
3 groups consisting of 4 students.
Mark can't be in the first group.
The combination formula that I used is: n! / r!(n-r)!
where: n = number of choices ; r = number of people to be chosen.
This is the formula I used because the order is not important and repetition is not allowed.
Since Mark can't be considered in the first group, the value of n would be 11 instead of 12. value of r is 4.
numerator: n! = 11! = 39,916,800
denominator: r!(n-r)! = 4!(11-4)! = 4!*7! = 120,960
Combination = 39,916,800 / 120,960 = 330
There are 330 ways that the instructor can choose 4 students for the first group
Use pathagoream theorem. You get the equation: 10^2=6^2+x^2 then solve and simplify to get x=8 So no Tom is not afraid of the heights
Answer: 6x²y
Explanation:
The LCM of the coefficients is 2*3 = 6
The LCM of the x terms is x²
The LCM of the y term is y
Put this all together to end up with the overall LCM being 6x²y
circumference = πD = π(20) = 62.83 cm (Nearest hundredth)
Answer: 62.83 cm
1318.4 x 10 to the third power
