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3 years ago

Describe how making a list can help you solve a math problem.

2 answers:

8 0

Making a list can help you solve a problem by:
•making more organized
•it can make it easier to organize data
•helps you stay on track

those are some of the basic ways,

larisa [96]3 years ago

7 0

Making a list can help you get your answer gives u ideas of what you are trying to do so you don't get lost and helps you on your answer.

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Your free ride to work ends in 14 days. So, maybe you need a car? How much can you afford to spend? Below is what's available at

garri49 [273]

Step-by-step explanation:

Kindly find attached a screenshot of the price list of some cars from motor 1 .com since you did not provide any in the question, and let us assume it is the same as what is available at a dealership near you.

From the list, since you don't have enough money in your account to buy a car, I will say you should get a 2017 Nissan Versa for $11,990

and 25% of $11,990 is

(25/100)* 11,990

0.25* 11,990

$2997.5

So you can make a down payment of $2997.5

and pay the remainder of $8992.5 later

6 0

3 years ago

Part 1 Write your own real-world scenario where the Pythagorean Theorem can be applied to find a missing piece. You may choose t

kondor19780726 [428]

I think this answers all the parts

Hope this helped :)

7 0

3 years ago

Rearrange to make x the subject of 4(x-3)/a=y

IrinaVladis [17]

Answer: x = a*y + 3

Step-by-step explanation:

To make x the subject of the equation, first, we open the bracket

4x - 12/a = y

Then cross multiply:

4x - 12 = a * y ( a*y means the product of the two variables)

Add 12 to both sides of the equation

4x = a*y + 12

Divide both sides by 4 to get the value of x

x = a * y + 12/4

x = a*y + 3

I hope this helps.

4 0

3 years ago

HELP PLEASE MATH!! A company is testing tires for wear and tear. A given tire is said to either pass the test (P) or fail the te

Xelga [282]

Answer:

PPF, PFF

Step-by-step explanation:

There are several ways you can list all the possible combinations. A couple of my favorite are a) use a binary counting sequence; b) use a gray code counting sequence.

Using the first method, the binary numbers 000 to 111 can be listed in numerical order as 000, 001, 010, 011, 100, 101, 110, 111. Letting 0=P and 1=F, the ones missing from your list are the ones in italics in my list.

Using the second method, we change the right-most character, then the middle one, and finally the left-most character so there is one change at a time: 000, 001, 011, 010, 110, 111, 101, 100.

After you have a list of all possible combinations, it is a simple matter to compare the given list to the list of possibilities to see which are missing.

5 0

3 years ago

Read 2 more answers

Simplify completely 12 times x to the third power minus 4 times x to the 2nd power plus 8 times x all over negative 2 times x

lawyer [7]

(12x^3-4x^2+8x)/(-2x) The greatest common factor of the numerator and denominator is -2x so upon division by GCF of both numerator and denominator you have:

-6x^2+2x-4 and we can now also factor out -2

-2(3x^2-x+2)

5 0

3 years ago