The two answers are the one selected and the choice |x-5| ≤ 1. The steps to solve the other equation are:
|x-5| ≤ 1
x-5 ≤ 1, x-5 ≥ 0
-(x-5) ≤ 6, x-5 is less than 0
x ≤ 6, x ≥ 5
x ≥ 4, x is less than 5
x ∈ [5,6]
x ∈ [4,5]
4 ≤ x ≤ 6
(^which was the original answer^)
Note that this just produces three parametric equations:
In the
plane, this is just he parametric equation for an ellipse (as a function of u). The z is simply a linear function.
The surface is then an ellipse extruded along the z-axis. We get a elliptic cylinder.
The area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
<h3>How to find the area of a trapezoid and rhombus?</h3>
The given pattern consists of rhombus and trapezoids
The formula for calculating the area of rhombus is expressed as:
A = pq/2
Area of trapezoid = 0.5(a+b)h
Given the following
height = 2in
a = 2in
b = 3in
Ara of rhombus = 1(4)/2 = 2 square inches
Area of the trapezoid = 0.5(2+3) * 2
Area of the trapezoid = 5 square inches
Hence the area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
Learn more on area of rhombus and trapezoid here: brainly.com/question/2456096
Answer:
x = -1 y = 3 and z =2
Step-by-step explanation:
that is the solution above
