I know I keep asking for help but I literally just got put back in my right grade pls help
1 answer:
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Answer:
x = 6
Step-by-step explanation:
let 'x' = BD
x/3 = 12/x
x² = 36
x =
x = 6
Answer:
The complete solution is
Step-by-step explanation:
Given differential equation is
3y"- 8y' - 3y =4
The trial solution is
Differentiating with respect to x
Again differentiating with respect to x
Putting the value of y, y' and y'' in left side of the differential equation
The auxiliary equation is
The complementary function is
y''= D², y' = D
The given differential equation is
(3D²-8D-3D)y =4
⇒(3D+1)(D-3)y =4
Since the linear operation is
L(D) ≡ (3D+1)(D-3)
For particular integral
[since
]
[ replace D by 0 , since L(0)≠0]
The complete solution is
y= C.F+P.I