The real solution occurs when the graph intersects the x axis,
In the problem shown, the graph does not intersect the x axis, therefore it has no real solution, this means that the answer must have a complex conjugate pair
The answer is
function f has exactly two complex solutions
The length of the hypothenuse or the value of x is equal to 19.53
Data;
- hypothenuse = x
- adjacent = 11.2
- opposite = 16
<h3>Pythagoras's Theorem</h3>
To solve this problem, we have to use Pythagoras's theorem which is used to find the missing side in a right angle triangle if we have at least two sides.
The formula for this is

Let's substitute the values and solve for the missing side

The length of the hypothenuse or the value of x is equal to 19.53
Learn more Pythagoras theorem here;
brainly.com/question/3317136
Let x be the number of $10 bills in Iago pocket.
1. If he has twice as many $1 bills as $10 bills, then he has (2x) $1 bills.
2. He has two fewer $20 bills than he does $10 bills, then he has (x-2) $20 bills.
3. He has three more $5 bills than $10 bills, then he has (x+3) $5 bills.
In total he has $160 that is x·10+2x·1+(x-2)·20+(x+3)·5.
Equate these two expressions and solve the equation:

Thus, he has
- 5 bills for $10;
- 10 bills for $1;
- 3 bills for $20;
- 8 bills for $5.
we can find the answer to this problem by thinking about it logically for a minute:
we know that she assigned "x" homework problems on Monday, so,
x=Monday
we also know that she assigned 13 more problems on Tuesday, so,
13=Tuesday
over the course of the two days she assigned a total of 23 homework problems.
to get the answer of how many problems she assigned on Monday, we have to do the total number of problems she assigned(23) minus the number of problems we know she assigned on Tuesday(13), so,
23-13=10
she assigned 10 problems on Monday.
Option b. 0.496
- Step-by-step explanation:
we know that
f(x)=0.01(2^{x})
The average rate of change is equal to
\frac{f(b)-f(a)}{b-a}
where
a=3
b=8
f(a)=f(3)=0.01(2^{3})=0.08
f(b)=f(8)=0.01(2^{8})=2.56
Substitute
\frac{2.56-0.08}{8-3}
\frac{2.48}{5}
0.496