∠xangle, x and \angle y∠yangle, y are supplementary angles. \angle y∠yangle, y measures 88^\circ88
1 answer:
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The equation looks like this 
. In an ellipse, a is always the bigger value, so a^2 = 25. This bigger value also tells us which axis is the major one. Sine the bigger value a is under the y^2 of the equation, the major axis is the y-axis. This is a vertical ellipse. The center is always found within a set of parenthesis that exist with the x^2 and the y^2. Since there are no parenthesis with either, there is no side to side movement, nor is there any up or down movement. So the center doesn't move from the origin (0, 0). The vertex is also along the major axis, and if a^2 is 25, then a = 5, so the vertices go up 5 from the center and down 5 from the center. Vertices are (0, 5) and (0, -5). The foci follow the formula 
. c is the distance that the foci are from the center. 
and c = 3. The foci also lie on the major axis, so the coordinates for the foci are (0, 3) and (0, -3). There you go!
Answer:
Step-by-step explanation:
As per the problem, the given triangle is a right triangle. This is signified by the box around one of its angles, this box states that the angle it is surrounding is a right angle.
Since it is a right triangle, one can use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that; (), where (
) and (
) are the legs of the right triangle, or the sides adjacent to the right angle. (
) is the hypotenuse or the side opposite the right angle.
Substitute in the given values and solve, note that () represents the unknown leg (side).
Inverse operations,