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pashok25 [27]
3 years ago
7

Please help me!! i’ll give brainliest the the best answer

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0
C. it’s a straight line. anything curved is NOT linear (*≧∀≦*)
algol [13]3 years ago
3 0

Answer:

C will be the answer for this

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What is the measure of ∠AOB?<br> 90°<br> 80°<br> 180°<br> 40°
zalisa [80]
I think it may be a 180 degree angle but I wouldnt trust myself so idk
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SpyIntel [72]

Answer:

Factor

Step-by-step explanation:

A factor is a number that is being multiplied.

A quotient is a number obtained by division.

A product is a number obtained by multiplication.

A coefficient is a number in front of a variable (2x).

6 0
3 years ago
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Six rectangles each with a common base width of 22 have lengths of 1,4,9,16,251,4,9,16,25, and 3636. What is the sum of the area
Angelina_Jolie [31]
22(1 + 4 + 9 + 16 +251 + 4 + 9 + 16 + 25 + 3636)
= 87362 units^2
8 0
2 years ago
Please help i’m so stuck i can’t do calc for the life of me
KATRIN_1 [288]

Answer:

-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}  is the answer. See steps below.

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}\\\\-3x^5+11x^4+33x^3-26x^2-36x-6\\\\\mathrm{and\:the\:divisor\:}x^3+6x^2-3x-5:\\\\\mathrm{Quotient}=\frac{-3x^5}{x^3}=-3x^2\\\\\mathrm{Multiply\:}x^3+6x^2-3x-5\mathrm{\:by\:}-3x^2\:\:\rightarrow\:\:-3x^5-18x^4+9x^3+15x^2\\\\\mathrm{Subtract\:}-3x^5-18x^4+9x^3+15x^2\mathrm{\:from\:}-3x^5+11x^4+33x^3-26x^2-36x-6\mathrm{\:to\:get\:new\:remainder}.\\\\\mathrm{Remainder}=29x^4+24x^3-41x^2-36x-6

=-3x^2+\frac{29x^4+24x^3-41x^2-36x-6}{x^3+6x^2-3x-5}

Repeat the steps and you will reach a point where no further division is possible.

<u />

<u />=-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}<u />

5 0
2 years ago
9. Triangle Construction pays Square Insurance $5,980
xxTIMURxx [149]

The triangle pay $32 more for that day than it paid per day during the first period of time.

Step-by-step explanation:

The given is,

              Triangle Construction pays Square Insurance $5,980

               To insure a construction site for 92 days

               To extend the  insurance beyond the 92 days costs $97 per day

               Triangle extends the insurance by 1 day

Step:1

              Insurance per day from the 92 days period,

                                                                           = \frac{Total insuratio for 92 days}{Period}

               Where, Total insurance for 92 days = $ 5,980

                                                               Period = 92 days

               From the values, equation becomes,

                                                                            =\frac{5980}{92}

                                                                           = $ 65 per day

Step:2

              Insurance per day after the 92 days,

                                                                           = $ 97

               Amount Pay for that day than it paid per day during the first period of time,

                                                                            =(97-65)

                                                                           = $32

Result:

             The triangle pay $32 more for that day than it paid per day during the first period of time, if  the Triangle Construction pays Square Insurance $5,980 to insure a construction site for 92 days and to extend the  insurance beyond the 92 days costs $97 per day.

                                                                         

8 0
3 years ago
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