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Troyanec [42]
3 years ago
6

Please help with this page

Mathematics
1 answer:
Serggg [28]3 years ago
4 0

area of first figure=444

area of second figure=57

area of third figure=132

Explanation

The first figure

has 9 faces, 2 triangular and 7 rectangular.

bottom face-rectangle

length=16

breadth=5

area=l*b=16*5=80(1)

two similar rectangular faces

length=16

breadth=4

area=l*b=16*4=64

area of two faces=2*64=128(2)

two similar rectangular faces

length=5

breadth=4

area=5*4=20

area of two faces=2*20=40(3)

two top slant faces-rectangular

length=10

breadth=5

area=10*5=50

area of two faces=2*50=100(4)

two triangular top faces

base=16

height=6

area=1/2 bh=1/2 *16*6=48

area of two faces=2*48=96(5)

total area of the structure=(1)+(2)+(3)+(4)+(5)=80+128+40+100+96=444

The  second figure

It has two triangles

triangle 1

length=7

breadth=3

area1=l*b=21

triangle 2

length=9

breadth=4

area2=l*b=9*4=36

total area=area1+area2=21+36=57

<u>T</u><u>he third  figure </u>

It has a rectangle and triangle

r<u>ectangle</u>

length=20

breadth=6

area1=l*b=20*6=120

triangle

base=20-(8+6)=20-14=6

height=10-6=4

area2=1/2 bh=1/2*6*4=12

total area=area1+area2=120+12=132

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Answer is c
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