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Answer:
trapezoid
Step-by-step explanation:
<em><u>Question:</u></em>
<em>Mrs. Magdalino kept records on how much she spent on gasoline and the maintenance of her car. She found that it cost $485 to drive 500 mi in a month.</em>
<em>a) Find the cost per mile. Write an equation that relates the cost c for gasoline and maintenance of a car to the number of miles m the car is driven.</em>
<em>b) Use the equation to find the cost for driving 1200 miles.</em>
<em>c) About how many miles are driven for a cost of $820?</em>
<em><u>Answer:</u></em>
a)
$485/500mi = <u><em>$0.97/mi</em></u>
c = cost
m = miles driven
cost per miles driven = cost / mile driven = <u><em>c/m</em></u>
b)
(1200 mi)*($0.97/mi) = <u><em>$1164</em></u>
c)
(x miles)*($0.97/mi) = $820
*divide both sides by $0.97/mi
x miles = $820/($0.97/mi)
<u><em>x = 845.36 miles</em></u>
