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morpeh [17]
3 years ago
8

Fabiano wants to score at least 6 . 5 6.5 points in a major chess tournament. He scores 1 1 point for each game that he wins, an

d he scores 0 . 5 0.5 points for each game that ends in a draw. Write an inequality that represents the number of games Fabiano should win ( W ) (W) and draw ( D ) (D) to achieve his goal.
Mathematics
1 answer:
Monica [59]3 years ago
8 0

Answer:

W+0.5D\geq 6.5

Step-by-step explanation:

Let W represent the number of games Fabiano should win and D represent the number games of Fabiano should draw.

We have been given that Fabiano scores 1 point for each game that he wins, so points scored in W games will be 1W=W.

We are also told that he scores 0.5 points for each game that ends in a draw. So points scored in D games will 0.5D.

As Fabiano wants to score at least 6.5 points in a major chess tournament, so total number of points scored in W games and D games should be greater than or equal to 6.5.

We can represent this information in an inequality as:

W+0.5D\geq 6.5

Therefore, the inequality W+0.5D\geq 6.5 represents the number of games Fabiano should win and draw to achieve his goal.

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A man travels 10km in 15min if he runs for 8km and walks for 2km if he runs 4cm and walks 6km his time is 1h 15min find his runn
MakcuM [25]

The running speed of the man is <u>16 km/hr.</u> and his walking speed is <u>6 km/hr.</u>, solved using the system of equations.

In the question, we are given that a man travels 10km in 50mins if he runs for 8km and walks for 2km. If he runs 4km and walks 6km, his time is 1h 15mins.

We are asked to find his running and walking speed.

We assume the running speed to be r km/hr., and the walking speed to be w km/hr.

<u>In the first case:-</u>

Distance he ran = 8km.

Thus, the time for which he ran = 8/r hr.

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Thus, the time for which he walked = 2/w hr.

Thus, the total time = 8/r + 2/w.

But, we are given that in the first case, he took 50 mins = 5/6 hours.

Thus, we get an equation, 8/r + 2/w = 5/6, or, 4/r + 1/w = 5/12 ... (i).

<u>In the second case:-</u>

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Thus, the time for which he ran = 4/r hr.

Distance he walked = 6km.

Thus, the time for which he walked = 6/w hr.

Thus, the total time = 4/r + 6/w.

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Thus, we get an equation, 4/r + 6/w = 5/4 ... (ii).

(i) and (ii) together gives us a system of equations.

Subtracting (i) from (ii), we get:

4/r + 6/w = 5/4.

4/r + 1/w = 5/12.

(-)   (-)        (-)

_____________

5/w = 10/12 = 5/6.

or, w = 6.

Substituting w = 6 in (ii), we get:

4/r + 6/w = 5/4,

or, 4/r + 6/6 = 5/4,

or, 4/r = 1/4,

or, r = 16.

Thus, the running speed of the man is <u>16 km/hr.</u> and his walking speed is <u>6 km/hr.</u>, solved using the system of equations.

Learn more about the system of equations at

brainly.com/question/14899496

#SPJ4

The provided question is incomplete. The complete question is as follows:

"A man travels 10km in 50mins if he runs for 8km and walks for 2km. If he runs 4km and walks 6km, his time is 1h 15mins. find his running and walking speed."

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