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morpeh [17]
3 years ago
8

Fabiano wants to score at least 6 . 5 6.5 points in a major chess tournament. He scores 1 1 point for each game that he wins, an

d he scores 0 . 5 0.5 points for each game that ends in a draw. Write an inequality that represents the number of games Fabiano should win ( W ) (W) and draw ( D ) (D) to achieve his goal.
Mathematics
1 answer:
Monica [59]3 years ago
8 0

Answer:

W+0.5D\geq 6.5

Step-by-step explanation:

Let W represent the number of games Fabiano should win and D represent the number games of Fabiano should draw.

We have been given that Fabiano scores 1 point for each game that he wins, so points scored in W games will be 1W=W.

We are also told that he scores 0.5 points for each game that ends in a draw. So points scored in D games will 0.5D.

As Fabiano wants to score at least 6.5 points in a major chess tournament, so total number of points scored in W games and D games should be greater than or equal to 6.5.

We can represent this information in an inequality as:

W+0.5D\geq 6.5

Therefore, the inequality W+0.5D\geq 6.5 represents the number of games Fabiano should win and draw to achieve his goal.

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The temperature falls from 0 degrees to Negative 12 and one-fourth degrees in 3 and one-half hours. Which expression finds the c
ANEK [815]

Answer:

The expression used to find the change in temperature per hour is Algebraic expression

Thus per hour; the temperature falls at the rate of - 3\dfrac{1}{2}^0

Step-by-step explanation:

A temperature falls from 0 to  - 12\dfrac{1}{4}     in     3\dfrac{1}{2} \ hours

Which expression finds the change in temperature per hour.

From the above given information;

The initial temperature is 0

The final temperature is  - 12\dfrac{1}{4}  

The change in temperature is \Delta T = T_2  -  T_1

\Delta  T = -12\dfrac{1}{4} -0

\Delta T = -12.25

Thus;

-12.25 ° = 3.5 hours

To find the change in x°   per hour; we have;

x°            = 1 hour

The expression used to find the change in temperature per hour is Algebraic expression

From above if we cross multiply ; we have;

(- 12.25° × 1 hour) = (x° × 3.5 hour)

Divide both sides by 3.5 hours; we have:

\dfrac{-12.25^0*1 }{3.5}=\dfrac{ x^0 *3.5}{3.5}

x° =  - 3.5

x° = - 3\dfrac{1}{2}

Thus per hour; the temperature falls at the rate of - 3\dfrac{1}{2}^0

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