Number of child tickets bought is 20
<h3><u>
Solution:</u></h3>
Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket
cost of each child ticket = 5 dollars
cost of each adult ticket = 8 dollars
Let "c" be the number of child tickets bought
Let "a" be the number of adult tickets bought
Total tickets sold were 110 bringing in 820 dollars
<em>Number of child tickets bought + number of adult tickets bought = 110</em>
c + a = 110 ----- eqn 1
<em><u>Also we can frame a equation as:</u></em>
Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

5c + 8a = 820 -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "c" and "a"
From eqn 1,
a = 110 - c ------ eqn 3
Substitute eqn 3 in eqn 2
5c + 8(110 - c) = 820
5c + 880 - 8c = 820
-3c = - 60
c = 20
Therefore from eqn 3,
a = 110 - 20 = 90
a = 90
Therefore number of child tickets bought is 20
Answer:
B) 8 ≤ p
Step-by-step explanation:
1000 - 380 = 620
620 / 80 = 7.75
Round it up to 8
Let us suppose the number is x. Now we try to make an algebraic expression going step by step.
Step 1:
Five times the number means 5 multiplied by x.
So it becomes 5x.
Step 2:
Sum of 14 and five times the number means 5x+14.
Step 3:
Number multiplied by -8 means -8x.
Step 4:
Subtract the expression in step (3) from expression in step (2)
5x+14-(-8x)
Now we can simplify it further,
5x+14+8x
Combining like terms,
13x+14
Answer: The final expression becomes 13x+14.
Answer:
ok the answer is: p=-4
Step-by-step explanation:
First you distribute 3 times p-4 and get 8-3p+12=2p then you add 12 plus 8 and get 20 then you have 20-3p=2p you have to add 3p on both sides and you get 20= -5p you divide and get p= -4
Answer:
aida's work is the correct answer