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Elenna [48]
3 years ago
14

How much is 5a(6b+12)

Mathematics
2 answers:
Nutka1998 [239]3 years ago
7 0
5a (6b+12)

5a*6b+5a*12

30ab+60a
 This is the answer
andreev551 [17]3 years ago
6 0
When writing an expression in expanded form, we just need to multiply what's outside the parentheses by everything that is inside the parentheses.

5a (6b + 12)

(5a * 6b) + (5a * 12)

30ab + 60a

And that is our answer.
5a (6b + 12) in expanded form is 30ab + 60a.
Hope that helped =)
You might be interested in
What is the 52nd term of the sequence below?
VladimirAG [237]
Because the difference between any term and the previous term is a constant, this is an arithmetic sequence because of that constant which is referred to as the common difference, d.  Which in this case is -35--38=-32--35=3

Any arithmetic sequence can be expressed as:

a(n)=a+d(n-1), a=initial term, d=common difference, n=term number.

In this case a=-38 and d=3 so

a(n)=-38+3(n-1)  which we can simplify to

a(n)=-38+3n-3

a(n)=3n-41, so the 52nd term is:

a(52)=3(52)-41

a(52)=156-41

a(52)=115
3 0
3 years ago
If 3x − (7 − x) = 29, find the value of 6x.
Stells [14]

Answer:

54

Step-by-step explanation:

3x -(7-x) = 29       remove the parens

3x - 7 + x = 29     simplify

4x -7 = 29            add 7 to both sides of the equation

4x = 36            divide by

x = 9

then 6x = 6 * 9 = 54

7 0
1 year ago
Please solve the problem ​
jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.

Then you can eliminate <em>Y</em> by taking the sum

4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>

==>   <em>X</em> = (4<em>A</em> + <em>B</em>)/11

Similarly, you can eliminate <em>X</em> by using

-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>

==>   <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11

It follows that

X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}

Similarly, you would find

Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}

You can solve the second system in the same fashion. You would end up with

P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}

3 0
3 years ago
What is the slope of the line do the point for me to?
larisa86 [58]

Answer:

Step-by-step explanation:

we can see that the line goes thru the point (-1,2) and (4,-2) now to find slope we just find change in y over change in x

more visually:

(y1-y2)/(x1-x2)

so for the point (-1,2) let’s say

-1 = x1

and

2 = y1

and for the point (4,-2) let’s say

4 = x2

and

-2 = y2

to find slope we plug in the values to our slope equation and we get this:

(2-(-2))/( -1-4)

(2+2)/-5

4/-5

so slope is -4/5

because to get from (-1,2) to (-4,-2) you have to move down 4 and to the right 5

6 0
3 years ago
49.2532 rounded to 1 decimal place
erastova [34]
The answer is 49.3!
5 0
3 years ago
Read 2 more answers
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