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goldfiish [28.3K]
3 years ago
6

The weight of the candy that Eric collected on Halloween was 1.3 kilograms. Timothy collected 1.8 kilograms of candy. How many m

ore grams of candy did Timothy collect?
Mathematics
2 answers:
nikitadnepr [17]3 years ago
6 0

Answer:

Timothy:

1.8 kilograms = 1.8 × 10 × 10 × 10 = 1,800 grams

Eric:

1.3 kilograms = 1.3 × 10 × 10 × 10 = 1,300 grams

Weight difference of candy:

1,800 g − 1,300 g = 500 grams

Step-by-step explanation:


Aleks [24]3 years ago
5 0
Since Timothy collected more, we take the amount Timothy collected and subtract the amount Eric collected from that.
1.8 - 1.3 = .5
That means Timothy collected .5 kilograms more candy than Eric.
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6 0
3 years ago
Read 2 more answers
Which answer is correct
andre [41]

Hello from MrBillDoesMath!

Answer:

The first choice,  Pi + (-Pi) = 0

Discussion:

Pi is an irrational number. Saying the irrational numbers <u>are</u> closed under addition means if we add two irrational numbers we will get another irrational number. In our case, Pi + (-Pi) = 0, which is correct, BUT 0 is a <u>rational </u>number. This shows the set of irrational numbers is NOT closed under addition.

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7 0
3 years ago
The designer sketched a model of the pond. The model drawing had a circumference of 24 inches. What is the AREA of the model she
Delicious77 [7]

Answer:

Area of model pond = 45.6 inch² (Approx.)

Step-by-step explanation:

Given:

Circumference of circular pond = 24 inches

Find:

Area of model pond

Computation:

Circumference of circle = 2πr

Circumference of circular pond = 2πr

24 = 2[22/7][r]

Radius r = [24 x 7] / [2 x 22]

Radius r = 3.81 inch (Approx.)

Area of circle = πr²

Area of model pond = πr²

Area of model pond = (22/7)(3.81)²

Area of model pond = [3.1428][14.5161]

Area of model pond = 45.6 inch² (Approx.)

6 0
3 years ago
chegg evaluate the following integral using trigonometric substitution. dx/square root(x^2-81), x &gt; 9
vesna_86 [32]

Integration will be ln | ( x /9 ) + ( \sqrt{(x/9)^{2} - 1 } ) | + c  .

Given  ∫ 1 dx / ( x^{2} - 81 )

Put ,

x = 9 secθ

dx = 9 secθ tanθ dθ

and

\sqrt{x^{2}  - 9^{2} } = 9 tanθ

Substituting values in  ∫ 1 dx / ( x^{2} - 81 ) ,

∫ (9 secθ tanθ ) dθ / ( 9 tanθ )

∫ secθ dθ = ln | secθ + tanθ | + c

                = ln | ( x /9 ) + ( \sqrt{x^{2}  - 9^{2} } / 9 ) | + c

              = ln | ( x /9 ) + ( \sqrt{(x/9)^{2} - 1 } ) | + c

Hence , the integration will be ln | ( x /9 ) + ( \sqrt{(x/9)^{2} - 1 } ) | + c .

To learn more on integration follow link :

brainly.com/question/20156869

#SPJ4

6 0
2 years ago
Solve for these letters<br> X<br> Y<br> Z
tester [92]
Z = 140
X = 40
Y = 40
Explanation:
Z and the angle given (140 degrees) are vertical angles, and are therefore congruent
We know that x and y are vertical angles, so they are also congruent to each other
You know that together, the angles have to add up to 360
140 + 140 + x + y = 360
Another way of putting it:
360-280 = 80
Now, we have to divide by two since we need to find x AND y
80/2 = 40
Therefore, your answers for x and y are 40
To double check, you can add up the angles and see if they equal 360
140 + 140 + 40 + 40
280 + 80 = 360
7 0
3 years ago
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