Answer:
4/8 and then 1/2so 1/2 is the final answer
Answer:
$8511.11
Step-by-step explanation:
Each year, the amount Walter owes is multiplied by 1.06, so at the end of 6 years, Walter owes 1.06^6 times the amount he borrowed.
he will pay $6,000×1.06^6 ≈ $8511.11
_____
At the end of the first year, Walter owes the original loan amount plus 6% interest. That total is ...
$6000 + 0.06×6000 = $6000×1.06
At the end of the following year, he owes 1.06 times that amount, or ...
6000×1.06²
The amount owed is multiplied by 1.06 each year until Walter pays off the loan.
Answer:
$199.02
Step-by-step explanation:
If the answer is right then I'm gonna explain it.
Step 1: Write the amount of savings in equation
Linda's savings: s=1.55d
Tyron's savings: m=3.90d
Step 2: Add on the extra days to Linda's savings
Linda's savings s=1.55d+3(1.55)
Step 4: Simplify equation
s=1.55d+3(1.55)
s=1.55d+4.66
Step 5: Substitute numbers for d days until Tyron's m savings is greater than Linda's s saving
m=3.90d s=1.55(2)+4.66
m=3.90(2) s=3.10+4.66
m=7.80 s=7.76
On Tyron's second day he will have more money in his savings than Linda does.
