Answer:
traffic , pollution, lack of space.
Explanation:
Answer:
It is established by the provisions of the Korean Armistice Agreement to serve as a buffer zone between North Korea and South Korea. The demilitarized zone (DMZ) is a border barrier that divides the Korean Peninsula roughly in half.
Explanation:
Derivative classifiers are required to have training every two years
Who needs derivative classification training?
All DoD personnel, including contractors, who access classified systems and networks or perform derivative classification functions are required to complete derivative classification training annually.
How many categories are there in derivative classification?
the information must concern at least one of the eight categories specified in section 1.4 of Executive Order 13526, Classified National Security Information.
What best describes derivative classification?
The process of paraphrasing, restating, or generating in new form information that is already classified, and marking the newly developed material consistent with the classification markings that apply to the source information.
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Answer:
more; less; irrelevant
Explanation:
A reinforcer may be defined as something which increases the chance of a response or a specific behavior to occur. It can be either negative or positive.
In the context, for Ginny who is 5 year old, there is a high chance to choose a more desirable and delayed reinforcer but a less desirable reinforcer if some irrelevant behavior is performed in the delay period.
Answer:
RrYy x RrYy
Explanation:
Given
Round (R) allele is dominant over wrinkled allele "r"
and Yellow seed allele (Y) is dominant over green seed allele "y"
If I find a plant with round and yellow seeds and want to determine its genotype, then I will cross it with plant that has heterozygous genotype for both the characteristics i.e "RrYy"
Let us say that the plant I found is heterozygous dominant for both the traits i.e "RrYy"
If RrYy is crossed with another RrYy ,we get -
RY Ry rY ry
RY RRYY RRYy RrYY RrYy
Ry RRYy RRyy RrYy Rryy
rY RrYY RrYy rrYY rrYy
ry RrYy Rryy rrYy rryy
Thus, the possible gnotypes would be
RRYY-1
RRYy-2
RrYY-2
RrYy-4
RRyy- 1
Rryy-2
rrYY-1
rrYy-2
rryy-1
The phenotypic ration for this cross is
. This is a standard cross result between two heterozygous parents.
