A triangle is translated by using the rule (XY)

If point p partitions line BA,what would be the part to whole ratio

IRINA_888 [86]

Answer:

4 / 5

Step-by-step explanation:

From the image attached, Line BA is divided into a total of 5 equal proportions (or intervals). Point P is placed at the 4th proportion of the divided line, also the distance between point P and point A is 1 propotion. The ratio in which point P divides the line BA is given as:

Ratio = BP : PA = 4 : 1

Ratio = 4 : 1

The part to whole ratio If point p partitions line BA = BP / BA = 4 / 5

Part to whole ratio = 4/5

3 0

2 years ago

What are all the possible rational roots of f(0) = 2x^4+ x^3+ 4?

ElenaW [278]

Answer: the answer is 4, just 4

7 0

2 years ago

For the scientific notation, write the standard form: 5.61 x 102

Alekssandra [29.7K]

I believe the exponential form above is 5.61 x $10^{2}$

Answer:

561

Step-by-step explanation:

A "scientific notation" is being used in order to express large numbers in its simplest form. This is commonly used in careers that use Mathematics very often like engineers or scientists because it makes their computation easier.

The "standard form" refers to the standard or traditional way of writing the numbers.

In order to get the standard form above, you have to check the "power of the number 10." The exponent above is 2. This means that you have to move the decimal point of 5.61 to the right twice. So, the answer is 561.

4 0

3 years ago

a. esteban-perez and j. m. morales ´ , distributionally robust stochastic programs with side information based on trimmings, mat

sleet_krkn [62]

Distributionally robust stochastic programs with side information based on trimmings

This is a research paper whose authors are Adrián Esteban-Pérez and Juan M. Morales.

Abstract:

We look at stochastic programmes that are conditional on some covariate information, where the only knowledge of the possible relationship between the unknown parameters and the covariates is a limited data sample of their joint distribution. We build a data-driven Distributionally Robust Optimization (DRO) framework to hedge the decision against the inherent error in the process of inferring conditional information from limited joint data by leveraging the close relationship between the notion of trimmings of a probability measure and the partial mass transportation problem.
We demonstrate that our technique is computationally as tractable as the usual (no side information) Wasserstein-metric-based DRO and provides performance guarantees. Furthermore, our DRO framework may be easily applied to data-driven decision-making issues involving tainted samples. Finally, using a single-item newsvendor problem and a portfolio allocation problem with side information, the theoretical findings are presented.

Conclusions:

We used the relationship between probability reductions and partial mass transit in this study to give a straightforward, yet powerful and creative technique to expand the usual Wasserstein-metric-based DRO to the situation of conditional stochastic programming. In the process of inferring the conditional probability measure of the random parameters from a limited sample drawn from the genuine joint data-generating distribution, our technique generates judgments that are distributionally resilient to uncertainty. In a series of numerical tests based on the single-item newsvendor issue and a portfolio allocation problem, we proved that our strategy achieves much higher out-of-sample performance than several current options. We backed up these actual findings with theoretical analysis, demonstrating that our strategy had appealing performance guarantees.

To learn more about probability, visit :

brainly.com/question/11234923

#SPJ4

7 0

1 year ago

A closed box with a square base is to have a volume of 13 comma 500 cm cubed. The material for the top and bottom of the box cos

andrezito [222]

Answer:

x = 1,5 cm

h = 6 cm

C(min) = 135 $

Step-by-step explanation:

Volume of the box is :

V(b) = 13,5 cm³

Aea of the top is equal to area of the base,

Let call " x " side of the base then as it is square area is A₁ = x²

Sides areas are 4 each one equal to x * h (where h is the high of the box)

And volume of the box is 13,5 cm³ = x²*h

Then h = 13,5/x²

Side area is : A₂ = x* 13,5/x²

A(b) = A₁ + A₂

Total area of the box as functon of x is:

A(x) = 2*x² + 4* 13,5 / x

And finally cost of the box is

C(x) = 10*2*x² + 2.50*4*13.5/x

C(x) = 20*x² + 135/x

Taking derivatives on both sides of the equation:

C´(x) = 40*x - 135*/x²

C´(x) = 0 ⇒ 40*x - 135*/x² = 0 ⇒ 40*x³ = 135

x³ = 3.375

x = 1,5 cm

And h = 13,5/x² ⇒ h = 13,5/ (1,5)²

h = 6 cm

C(min) = 20*x² + 135/x

C(min) = 45 + 90

C(min) = 135 $

8 0

3 years ago