X + (-9) = 32 What is the answer

Mathematics

2 answers:

iren2701 [21]2 years ago

6 0

X=41 will be the answer for this

bezimeni [28]2 years ago

3 0

Answer:

the answer to x+(-9)=32 is x=41

You might be interested in

If C = t - 5 and B = t^2 + 2, find an expression that equals 2C + 2B in standard<br> form.

adell [148]

Answer:

t² + t - 3 = 0

Step-by-step explanation:

C = t - 5

B = t² - 2

2C + 2B

= 2(t - 5) + 2(t² + 2)

= 2t - 10 + 2t² + 4

= 2t² + 2t - 6

=> t² + t - 3 = 0

8 0

2 years ago

Simplify leaving your answer with positive exponents.

vaieri [72.5K]

$\bf \left( \cfrac{5m^{\frac{4}{3}}}{n^{\frac{2}{3}}} \right)^{-\frac{2}{3}}\left(\cfrac{m^4}{8n^5} \right)^{-\frac{4}{3}}\implies 
\left( \cfrac{n^{\frac{2}{3}}}{5m^{\frac{4}{3}}} \right)^{\frac{2}{3}}\left(\cfrac{8n^5}{m^4} \right)^{\frac{4}{3}}\impliedby 
\begin{array}{llll}
\textit{and now we}\\
\textit{distribute}\\
\textit{the exponent}
\end{array}$

$\bf \left( \cfrac{n^{\frac{2}{3}\cdot \frac{2}{3}}}{5^{\frac{2}{3}}m^{\frac{4}{3}\cdot \frac{2}{3}}} \right)\left( \cfrac{8^{\frac{4}{3}}n^{5\cdot \frac{4}{3}}}{m^{4\cdot \frac{4}{3}}} \right)\implies \cfrac{n^{\frac{4}{9}}}{5^{\frac{2}{3}}m^{\frac{8}{9}}}\cdot \cfrac{8^{\frac{4}{3}}n^{\frac{20}{3}}}{m^{\frac{16}{3}}}\implies \cfrac{8^{\frac{4}{3}}n^{\frac{4}{9}+\frac{20}{3}}}{5^{\frac{2}{3}}m^{\frac{8}{9}+\frac{16}{3}}}$

$\bf \cfrac{8^{\frac{4}{3}}n^{\frac{4+60}{9}}}{5^{\frac{2}{3}}m^{\frac{8+48}{9}}}\implies \cfrac{8^{\frac{4}{3}}n^{\frac{64}{9}}}{5^{\frac{2}{3}}m^{\frac{56}{9}}}$

4 0

3 years ago

I need help on these two problems

sattari [20]

50. since n_1/4<1 the equation is not true. it has no solution.
48. same thing since 45 <= z the equation is not true.

6 0

3 years ago

Which expression represents”9 less than the product of 5 and a number n”?

Alika [10]

9 less means subtract

the product of 5 and the number n mea multiply 5 and n

D. 5n-9