3 years ago

3x+6y=36 and -3x-6y=0

Mathematics

1 answer:

Anastasy [175]3 years ago

4 0

Answer:

No solution

Step-by-step explanation:

3x + 6y =36

-3x - 6y =0

------------------add

0 ≠ 36

No solution

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M is the midpoint of PQ. The diameter of a circle O is 13 in. And RM = 4 in.

garri49 [273]

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Part a) $PM=6\ in$

Part b) $PQ=12\ in$

Step-by-step explanation:

step 1

we know that

The diameter of the circle divide the circle into two equal parts

PM=MQ

Applying the Intersecting Chord Theorem (When two chords intersect each other inside a circle, the products of their segments are equal)

$SM*RM=PM*MQ$

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we have

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substitute

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step 2

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we know that

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we have

$PM=6\ in$

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3 years ago

3x+6y=36 and -3x-6y=0​

3x+6y=36 and -3x-6y=0