Answer:
ok so it would be square root 2
Step-by-step explanation:
What grade are u in? I’m pretty sure we’re doing the same assignment I was gonna upload that photo to brainly for help but uh
Answer:
The first derivative of 
is 
.
Step-by-step explanation:
Let . we can determine its first derivative by Rule for the Square Root Function, Rule for Power Function, Rule of Chain and Rule for the Addition of Functions, Rule for the Subtraction of Functions, Rule for the Division of Functions:
![y' = \frac{1}{2}\cdot \sqrt{\frac{1+x}{1-x} }\cdot \left[\frac{-1-x-1+x}{(1+x)^{2}} \right]](https://tex.z-dn.net/?f=y%27%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Csqrt%7B%5Cfrac%7B1%2Bx%7D%7B1-x%7D%20%7D%5Ccdot%20%5Cleft%5B%5Cfrac%7B-1-x-1%2Bx%7D%7B%281%2Bx%29%5E%7B2%7D%7D%20%5Cright%5D)
![y' = \frac{1}{2}\cdot \sqrt{\frac{1+x}{1-x} } \cdot \left[-\frac{2}{(1+x)^{2}} \right]](https://tex.z-dn.net/?f=y%27%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Csqrt%7B%5Cfrac%7B1%2Bx%7D%7B1-x%7D%20%7D%20%5Ccdot%20%5Cleft%5B-%5Cfrac%7B2%7D%7B%281%2Bx%29%5E%7B2%7D%7D%20%5Cright%5D)
The first derivative of is .
x^3 − 2y^2 − 3x^3 + z^4
Plug in 3 for x, 5 for y, and -3 for z (given)
(3)^3 -2(5^2) - 3(3^3) + (-3)^4
Simplify
(3)^3 = 3 x 3 x 3 = 27
-2(5^2) = -2 x 25 = -50
-3(3^3) = -3 x 27 = -81
(-3)^4 = -3 x -3 x -3 x -3 = 9 x 9 = 81
Combine all the terms
27 + (-50) - 81 + 81
27 - 50 - 81 + 81
-23 + 0
-23
-23, or (C) is your answer
hope this helps
