Answer:
x ≥ -5
Step-by-step explanation:
If we have a translation to left c units, we write " x + c " in the function, and
If we have a translation to right c units, we write " x - c" in the function
If we have vertical translation up b units, we "add b to the function", and
If we have vertical translation down b units, we "subtract b to the function"
The parent function is 
Since translation left 5 units and up 3 units, we can write:

The domain is affected by the square root sign and we know the number under the square root CANNOT be negative, so we can say:
x + 5 ≥ 0
x ≥ -5
This is the domain.
Answer:
1 / q^30.
Step-by-step explanation:
[(p^2)(q^5)]^-4 * [(p^-4)(q^5)]^-2
Using the law (a^b)^c = a^bc :-
= p^-8 * q^-20 * p^8 * q^-10
= p^(-8+8) * q^(-20-10)
= p^0 * q^-30
= 1 * q^-30.
= 1 / q^30.