<span>n = 11<span>.
Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.
Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.
Together, they sold n-10+n-2=2n-12 boxes.
We know that they sold less than n boxes, so our inequality would be
2n-12<n.
To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.
Add 12 to both sides:
n-12+12<0+12; n<12.
This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.
If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box. </span></span>
Answer:I forgot how to solve that
Step-by-step explanation:
Answer:
1. x = 8
2. y = 1/2
Step-by-step explanation:
1. Plug the function
5x + 20(0.50) = 50
= 5x + 10 = 50
Subtract 10 from both side
= 5x = 40
Divide 5 on both sides
= x = 8
2. Plug in the function
5(8) + 20y = 50
= 40 + 20y = 50
Subtract 40 on both sides
= 20y = 10
Divide 20 both sides
= y = 10/20 | 1/2
Answer:
300
Step-by-step explanation:
15 * 20 = 300
she spent 3/5 * 300 = 180
and saved 2/5 * 300 = 120
Step-by-step explanation: last year
