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Lisa [10]
3 years ago
11

Combining Like Terms to Solve Equations q/3+7=12 show how you got the answer

Mathematics
2 answers:
ANEK [815]3 years ago
8 0

Answer:

q=15

Step-by-step explanation:

First, you subtract 7 from both sides of q/3+7=12 and you will get q/3=5. Then you multiply both sides by 3 and you get q=15.

algol133 years ago
7 0

Answer:

Step-by-step explanation:

ok i am assuming q and 3 are being divided

q/3+7=12

     -7     -7

q/3=5

*3     *3

q=15

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Sam is using the expression 8mn in class. What is the value of the expression when m = 4 a n d n = 12 ?
goldfiish [28.3K]

Answer:

8 x 4 x 12 = 384

Step-by-step explanation:

8 x 4 x 12 = 384

4 0
3 years ago
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What is the equation of the line through the origin and (-5, 6) <br><br>I hate try it's .-.​
vazorg [7]

Answer:

y=-\frac{6}{5} x

Step-by-step explanation:

y=-6/5x+0

y=-6/5x

6 0
2 years ago
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The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation
aliina [53]

Answer:

a.  X~N(2,885, 651)

b.  0.086291

c.  0.00058

d.  3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting  the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

P(X

#substitute the given values in the formula to solve for P:

P(X

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058

Hence, the proportion of customers consuming over  5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0
3 years ago
Round 67,436,828,104 to the nearest million
S_A_V [24]
It would be 67,437,000,000 since the eight in 67,436,(8)28,104 rounds the 6 up to a 7.
4 0
2 years ago
Read 2 more answers
How do you answer this step by step
leonid [27]
X/3 +4 = 5+x/6
6(x/3 +4 = 5+x/6)
2x+ 24 = 30 +x 
x= 6
3 0
2 years ago
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