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aliya0001 [1]
3 years ago
11

I need help with this question please

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
5 0

Answer:

  62

Step-by-step explanation:

The enclosing rectangle is 24 units long and 12 units high. Its area is ...

  (24 units)(12 units) = 288 square units

The white circles obviously cover more than half the area, so the only viable answer choice is 62.

__

If you want to go to the trouble to actually figure it out, you can find the area of each circle using the area formula ...

  A = πr² = (3.14)(6²) = 113.04

Then both circles have an area of 2×113.04 = 226.08, and the shaded area is the difference between that and the rectangle area:

  shaded area = 288 -226.08 = 61.92 ≈ 62

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Answer:

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Step-by-step explanation:

Since you have an angle trisector, in this case, <em>m</em>∠<em>CBE</em><em> </em>≅ <em>m</em>∠<em>DBA,</em><em> </em>therefore you <em>set</em><em> </em><em>x</em><em> </em>equal to 8, plus, according to Morley's Trisector Theorem, all three angles form an equilateral triangle, so <em>m</em>∠<em>BOC</em><em> </em>also has to equal 24°:

{8}^{2}  - 5(8) = 64 - 40 = 24 \\  \\ 6(8) - 24 = 48 - 24 = 24 \\  \\ 2(8) - y = 24 >> 16 - y = 24 >>  -8 = y

Then, <em>m</em>∠<em>ABC</em><em> </em>comes from multiplying 3 by 24 [three <em>twenty-</em><em>four</em>'s], which results in 72°.

I am joyous to assist you anytime.

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