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marysya [2.9K]
3 years ago
14

A particle moves on a line away from its initial position so that after t hours it is s = 2t^2 +3t miles from its initial positi

on. Find the average velocity of the particle over the interval [1, 4]. Include units in your answer.
Mathematics
1 answer:
Vaselesa [24]3 years ago
4 0

Answer:

Average speed of the particle is 13 miles per hour.

Step-by-step explanation:

From the given question expression for distance traveled by the particle is

s=2t^{2}+3t

Then fro the time interval (1, 4) we have to calculate the average speed.

At t=1, s=2(1)²+3(1) =2+3 =5 miles

And at t = 4 s=2(4)²+3(4) = 2(16)+12 = 32+12 =44 miles

So displacement of the particle in the time span from 1 to hours.

s = (44-5) = 39 miles

And the times taken = (4-1) =3 hours

From the formula speed = displacement/(time taken for displacement)

V = 39/3 = 13 miles/hour



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Part 2) The measure of the interior angles are 64°-67°-49°

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the value of x

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

In this problem

(3x-17)^o+(x+40)^o+(2x-5)^o=180^o

Solve for x

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step 2

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