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katen-ka-za [31]
3 years ago
8

(a²b²-c²)(a²b²+c²)simplify​

Mathematics
2 answers:
Anestetic [448]3 years ago
8 0

Answer:

a^4b^4 - c^4.

Step-by-step explanation:

(a²b²-c²)(a²b²+c²)

Difference of 2 squares:

= (a²b²)^2 - (c²)^2

= a^4b^4 - c^4.

liraira [26]3 years ago
6 0

Answer:

a⁴b⁴ - c⁴

Step-by-step explanation:

The difference of squares formula states that (a - b)(a + b) = a² - b². In this case, a = a²b² and b = c² so a² - b² = (a²b²)² - (c²)² = a⁴b⁴ - c⁴.

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Someone pls help asap this is due tmrw !!<br><br> x - 3y = -12<br> 2x + 3y = 3
hram777 [196]

Answer:

Step-by-step explanation:

to solve this system of equations we will add them

x-3y=-12

2x+3y=3 now +3y-3y=0

3x=-12+3

3x=-9

x=-3

plug in the first equation

-3-3y=-12

-3y=-12+3

-3y=-9

y=3

4 0
3 years ago
What is the result when 12x} + 17x² + 18x + 9 is divided by 4x + 3?
melamori03 [73]

Answer:

17x^2+31x+3

Step-by-step explanation:

4 0
3 years ago
a marble was randomly selected from a bad containing 3 red marbles , 3 blue marbes and 3 green marbles . what is the probability
galina1969 [7]

Answer:

\frac{1}{3}

Step-by-step explanation:

If there are 9 marbles in total and the desired outcome is to pick a green marble then the probability is \frac{desired outcome}{totaloutcomes} = \frac{3}{9} which simplifies down to a third.

8 0
3 years ago
Read 2 more answers
The area of a rectangle is 4.9 square units. The length is 2.5 units and the width is y units. What is the value of y?
iris [78.8K]
1.96, if you multiply that by the length, (which is 2.5) then you will get the area of 4.9 hope this helps
4 0
3 years ago
Read 2 more answers
Delta Airlines' flights from Boston to Seattle are on time 70 % of the time. Suppose 6 flights are randomly selected, and the nu
emmainna [20.7K]

Answer:

P(at least 4)  = 0.74431

Step-by-step explanation:

Here

Probability of the flights on time is = 70% = 70/100= 0.7

q= 0.3

n= 6

As the probability of success and failure is constant and the n is also fixed then the binomail probability distribution can be used to solve this.

P (x= 4) = 6c4 *(0.7)^4 (0.3)^2= 15*0.2401* 0.09= 0.324135

P (x= 5) = 6c5 *(0.7)^5(0.3)^1= 6*0.16807* 0.3=0.302526

P (x= 6) = 6c6 *(0.7)^6 (0.3)^0= 0.117649P

P (x= 0) = 6c0 *(0.7)^0 (0.3)^6= 0.000729

P (x= 1) = 6c1 *(0.7)^1 (0.3)^5=0.010206

P (x= 2) = 6c 2*(0.7)^2 (0.3)^4=0.059535

P (x= 3) = 6c3 *(0.7)^3 (0.3)^3=0.18522

Probability of at least 4 means that probability of greater than 4 inclusive of 4.

This can be obtained in two ways.

First is by subtracting the probabilities of less than 4.

Second is by adding probabilities greater than 4 including 4.

We get the same answer with any of the two methods used.

P(at least 4) = 1- P(x<4)

                     = 1- [ 0.000729+ 0.010206 +0.059535+ 0.18522]

                     = 1- 0.25569

                       = 0.74431

P (at least 4) = P(x=4) +P(X=5) + P(x=6)

                        =0.324135+ 0.302526+ 0.117649

                        =0.74431

7 0
3 years ago
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