Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
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Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
Answer:
15
Step-by-step explanation:
38=10+13+c
c=38-10-13=15
Hope this helps!
Answer: 20 Decibels
Step-by-step explanation:
I don't know
Answer:
The correct answer is 25
Step-by-step explanation:
See the attached figure.
SAS similarity theorem mean that when two triangles have corresponding angles are congruent and corresponding sides with identical ratios the triangles are similar.
So, if ΔONM similar ΔSRQ by the SAS similarity theorem
∴∠N = ∠R
And
given that NM = 10 , NO = 8 , QR = x , RS = 20
∴
∴
So, the value of x will make ONM similar SRQ by the SAS similarity theorem = 25
