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bija089 [108]
4 years ago
7

Can someone please help me with question 9. Somebody answered it but this is the full question

Mathematics
1 answer:
zmey [24]4 years ago
3 0
You divide
77/1.54=50
The answer is £50
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A cyclist is riding from the city to the country. She rides 20 miles each hour. At the beginning of the 1 st hour, she is 10 mil
strojnjashka [21]

Answer:

450miles

Step-by-step explanation:

Because she is riding at 20 miles per houre means that she ride 450 miles in 5 houre.

7 0
2 years ago
Ma<br>Find the co-ordinate the image of a <br>point 6,4). Rotate it than<br>270<br>de acee​
telo118 [61]

Answer:

(4, - 6 )

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 270°

a point (x, y ) → (y, - x ) , thus

(6, 4 ) → (4, - 6 )

6 0
4 years ago
Question in photo, please help. This is the last one
jeka94
The answer is the last one
4 0
3 years ago
Given the following equation, explain which statement is correct
Vinvika [58]
A. The equation is true.


67+33=100
70+30=100
100=100 so yes, the equation is equal.
7 0
3 years ago
Read 2 more answers
Avani wrote the linear equation y = 5 x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5 x + 4 and t
Margarita [4]

Avani wrote the linear equation y = 5x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5x+ 4 and that passes through (15,–2). If her new equation is in the form  y-\frac{1}{5}x+b, what is the value of b?

\bf y=mx+b

  • m is the slope
  • b is the y-intercept

The equation of a line that is perpendicular to another line always has the opposite reciprocal slope. In the original equation, the slope is 5. The opposite of 5, which refers to the sign, is -5. The reciprocal of -5 is -1/5. That means the slope of the new line is -1/5.

The perpendicular line:

  • Has a slope of -\frac{1}{5}
  • Passes through the point (15, -2)

To find the equation of a line that passes through a specific point, you need to use slope-intercept form.

\bf y-y_{1} =m(x-x_{1})

  • y₁ is the y-value of the point
  • m is the slope
  • x₁ is the x-value of the point

y₁ is -2, m is -1/5,  and x₁ is 15.

Substitute the known values into the equation:

y-(-2)=-\frac{1}{5}(x-15) \rightarrow y+2= -\frac{1}{5}(x-15)

Open the parentheses and distribute:

-\frac{1}{5}(x-15) \rightarrow -\frac{1}{5} \cdot x\ +  -\frac{1}{5} \cdot -15 \rightarrow -\frac{1}{5}x +3

The new equation will be:

y+2=-\frac{1}{5}x+3

Lastly, you need to move the positive 2 to the other side to keep it in y = mx + b form.

y+2-2=-\frac{1}{5}x+3-2 \rightarrow y=-\frac{1}{5}x+1

The equation of the perpendicular line is:

\bf y=-\frac{1}{5}x+1

The value of b is 1.

5 0
3 years ago
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