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sesenic [268]
3 years ago
15

Two cars, each with a different volume of gas in their tanks, start moving at the same time. However, the volume of gas in their

tanks is used up at different rates. Assume the volumes are changing linearly. Volume in Tank (gal) Time (hr)15Car A17.2514.25Car B1915 How many hours will it take before both tanks have the same volume of gas in it?
Mathematics
1 answer:
kari74 [83]3 years ago
6 0

Answer:

8 hours

Step-by-step explanation:

−0.75x + 18 = -x+20

0.25x = 2

x = 8

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Super easy, just try it :) (this question is just for more cred)
Oksanka [162]

Answer:

32 is right answer, option d

5 0
3 years ago
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Sylvia launches a bottle rocket into the air. The function h(t)= 115t-16t^2 gives the height of the bottle rocket, in feet, seco
marin [14]

Answer:

4 seconds to reach 200 feet

Step-by-step explanation:

You can use Desmos (graphing calculator) then plug in the equation and you will find the x-values are 7.188 and 0- the origin.

Divide 7.188 by 2 (this is also solving for the midpoint/axis of symmetry) and you get 3.594

Round 3.594 to the nearest second which would be 4 seconds.

Hope that helps and have a great day!

3 0
3 years ago
If you buy 3 shirts, you get 10% discount. If you paid $270 for 6 shirts
earnstyle [38]

Answer:

50$

Step-by-step explanation:

270/6=45

10% of 50 is 5

so 50-5= 45

6 0
3 years ago
Read 2 more answers
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
Can someone help me please????
Ilia_Sergeevich [38]

Answer:


Step-by-step explanation:

trapezium area

A=a+b/2(h)

Whole: A=8+10/2(6)

A=54 cm

Hole: 5+7/2(3)

a=18

54cm-18cm= 36

area of shaded region is 36cm.

6 0
3 years ago
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