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Stels [109]
3 years ago
6

Please help me on these!! 40 points

Mathematics
2 answers:
Vlad1618 [11]3 years ago
7 0
8) The 4x should have been subtracted from the 8x instead of beating added

9) combine the like terms which are -18x and 5x
Otrada [13]3 years ago
4 0

Answer:

8: when they added -4x and 8x they didn't carry the negative

9: You add -18x and 5x              -13x - 12 = 1

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Which set is finite?
Tanzania [10]
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Answer A is the only finite set.
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How many students catch the train?<br><br> Thank you for helping.
Lunna [17]

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35

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8 0
1 year ago
Okay...last time i ask. 4ths times a charm i suppose. please help. will mark brainliest. ill even write you a frickisagfbsdfn po
barxatty [35]

Ok, so when it says "3x, x\leq2," it means that when the x value is less than or equal to 3, you graph 3x. You would have the following points on the line: (-3,-9), (-2,-6), (-1,-3), (0,0), (1,3), and (2,6). The endpoint of the ray on the left side (the points I just said) would be (2,6)

When it says, "1/2 x +5, 2\leqx," it means that when the value of x is greater than or equal to 2, the y value is .5x + 5. You would graph the following points: (2,6), (4,7), (6,8), and (8,9). The endpoint of th ray on the right (the points I just said) would be (2,6).

Keep in mind that though the graph is continuous, it isn't one line, but 2 rays (which you probably already know).

6 0
3 years ago
What is a1 of the arithmetic sequence for which a3=126 and a64= 3,725
Dominik [7]

If the third term of the aritmetic sequence is 126 and sixty fourth term is 3725 then the first term is 8.

Given the third term of the aritmetic sequence is 126 and sixty fourth term is 3725.

We are required to find the first term of the arithmetic sequence.

Arithmetic sequence is a series in which all the terms have equal difference.

Nth term of an AP=a+(n-1)d

A_{3}=a+(3-1)d

126=a+2d--------1

A_{64}=a+(64-1)d

3725=a+63d------2

Subtract second equation from first equation.

a+2d-a-63d=126-3725

-61d=-3599

d=59

Put the value of d in 1 to get the value of a.

a+2d=126

a+2*59=126

a+118=126

a=126-118

a=8

A_{1}=a+(1-1)d

=8+0*59

=8

Hence if the third term of the arithmetic sequence is 126 and sixty fourth term is 3725 then the first term is 8.

Learn more about arithmetic progression at brainly.com/question/6561461

#SPJ1

3 0
2 years ago
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