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Lisa [10]
4 years ago
6

Using FOIL, solve (t + 2bs^2) (2t-3bs^2) please show all the steps.

Mathematics
2 answers:
Ahat [919]4 years ago
8 0
2t^2+-6b^2s^4+4bs^2t-3bs^2t

 so 2t^2-6b^2s^4+bs^2t is your answer 
lions [1.4K]4 years ago
4 0
Foil
first
outer
inner
last
example if you had
(x+y)(z+t)
first x times z
outer x time t
inner y times z
last y times t


so

FOIL
(t+2bs^2)(2t-3bs^2)
FIRST (t times 2t=2t^2)
Outer (t times -3bs^2=-3tbs^2)
Inner (2bs^2 times 2t=4tbs^2)
Last (2bs^2 times -3bs^2=-6b^2s^4)

now add
2t^2-3tbs^2+4tbs^2-6b^2s^4
add like terms (-3tbs^2+4tbs^2=1tbs^2=tbs^2)
2t^2+tbs^2-6b^2s^4
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Help asap thank you!!!!!
viktelen [127]

Answer:

A = 120

C = 45

Step-by-step explanation:

(12x + 12) + 15 + (3x + 18) = 180

(12x + 3x) + (12 + 15 + 18) = 180

15x + 45 = 180

15x = 180 - 45

15x = 135

x = 135/15

x = 9

A = 12x + 12 = 12(9) + 12 = 108 + 12 = 120

C = 3x + 18 = 3(9) + 18 = 27 + 18 = 45

6 0
3 years ago
Right and solve an equation to find the number n.four times a difference of a number and seven is 12
amm1812

For this case we must propose an algebraic expression associated with:

"four times a difference of a number and seven is 12"

So we have to:

Four times a difference of a number and seven is represented as: 4 (n-7)

So we have the expression is:

4 (n-7) = 12

We apply distributive property to the terms within parentheses:

4n-28 = 12

We add 28 to both sides:

4n = 12 + 28\\4n = 40

We divide between 4 on both sides:

n = \frac {40} {4}\\n = 10

Answer:

n=10

5 0
4 years ago
Area of circumstances of a circle with radius of 5
Ilya [14]
Circumference of a Circle = 2πr
2 π 5
approx 31.41

Area of a Circle πr^2

π5^2
Approx 78.53
4 0
2 years ago
If the sum of the interior angles of a polygon is 2340, how many sides does the polygon have?
My name is Ann [436]

Answer:

15

Step-by-step explanation:

Where n represent no.of sides

(2n-4)90=2340

180n-360=2340

180n=2340+360

180n=2700

n=15

7 0
3 years ago
HELP PLSSSSSSSSSS!!!!!!!!<br> PLS SOLVE BOTH!!!!!! PLSSSSSSSS
timama [110]

Answer:

use photomath

Step-by-step explanation:

6 0
3 years ago
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