Area of circumstances of a circle with radius of 5
1 answer:
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Answer:
Step-by-step explanation:
3v + u + 66 = 360
<em>Subtract 66 from 366</em>
3v + u = 294
<em>check images</em>
<em>for more steps</em>
Area of a regular polygon = 1/2 x apothem x perimeter
We know that each side is 10, because if you draw a segment from the center to a vertex it creates a 30-60-90 triangle (those are the angles). This type of triangle has a ratio for its sides where the longer side is radical three times as long as the shorter leg. This shorter leg happens to be half of a side of the polygon. Knowing that the polygon has 6 sides, we can multiply 10 by 6 to get the perimeter.
Area of polygon = 1/2 x apothem x perimeter = 1/2 x 5
x 60
=30 x 5
= 30 x 5 x <span>1.73205080757
= 150 x </span><span>1.73205080757
= </span><span>259.807621135
To the nearest tenth of a cm, the area of the polygon is 260 cm squared</span>
We know that each side is 10, because if you draw a segment from the center to a vertex it creates a 30-60-90 triangle (those are the angles). This type of triangle has a ratio for its sides where the longer side is radical three times as long as the shorter leg. This shorter leg happens to be half of a side of the polygon. Knowing that the polygon has 6 sides, we can multiply 10 by 6 to get the perimeter.
Area of polygon = 1/2 x apothem x perimeter = 1/2 x 5
=30 x 5
= 30 x 5 x <span>1.73205080757
= 150 x </span><span>1.73205080757
= </span><span>259.807621135
To the nearest tenth of a cm, the area of the polygon is 260 cm squared</span>