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Sphinxa [80]
3 years ago
11

Can you please help me answer this quest6

Mathematics
1 answer:
EleoNora [17]3 years ago
3 0
Its a 90 degree right angle because of how two of the segments in the triangle are shaped like a perfect letter L

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Can someone tell me answer plz
Vinil7 [7]

The answer would be A

6 0
3 years ago
Read 2 more answers
3. A dish contains 100 candies. Juan removes candies from the dish each day and no
iVinArrow [24]

Answer:

11

Step-by-step explanation:

If i am correct n= the days so with the days adding up day 10 juan would have 55 of the 100 candies, day 11 he would have 66. The statement said at least 64, so it would have to be 64 or the closet amount to 64 but it cannot be lower than 64. So there for 66 is the closest to the given amount, and in order for juan to get 64 he would need to take candies out for 11 days.

7 0
2 years ago
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0
3 years ago
Jazmin is completing an art project. She has two pieces of construction paper. The first piece is 44 inches wide and the second
Yuliya22 [10]
One piece of paper is 44 and the other is 33

she can cut each strip where it is 11 inches in width
4 0
3 years ago
I need help this is the question.
tino4ka555 [31]

Let <em>x</em> = 3.191919…. Then 100<em>x</em> = 319.191919…, and we have

100<em>x</em> - <em>x</em> = 319.191919… - 3.191919…

99<em>x</em> = 316

<em>x</em> = 316/99

Next, we have

316 = 297 + 19 = 3 × 99 + 19

so

316/99 = (3 × 99 + 19)/99 = 3 + 19/99

4 0
3 years ago
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