<h3>
Answer: 28</h3>
==========================================================
Explanation:
Method 1
Imagine a table with 8 rows and 8 columns to represent all possible match-ups. You can actually draw out this table or just think of it as a thought experiment.
There are 8*8 = 64 entries in the table. Along the northwest diagonal, we have each team pair up with itself. This is of course silly and impossible. We cross off this entire diagonal so we drop to 64-8 = 56 entries.
Then notice that the lower left corner is a mirror copy of the upper right corner. A match-up like AB is the same as BA. So we must divide by 2 to get 56/2 = 28 different matches.
----------------------------------
Method 2
There are 8 selections for the first slot, and 8-1 = 7 selections for the second slot. We have 8*7 = 56 permutations and 56/2 = 28 combinations.
----------------------------------
Method 3
Use the nCr combination formula with n = 8 and r = 2

There are 28 combinations possible. Order doesn't matter (eg: match-up AB is the same as match-up BA).
Notice how the (8*7)/2 expression is part of the steps shown above in the nCr formula.
Answer:
p < 5
I think this is the answer?..
To determine the median, we need to set up our numbers from least to greatest, and then place T in later to figure out what T is.
8, 9, 9, 9, 10, 11, 12, 15. Cross out the smallest number with the largest number.
9, 9, 9, 10, 11, 12.
9, 9, 10, 11.
9, 10.
9.5 is our median currently.
Since we need to get a number after 10 to make 10 the median, let's use 12.
8, 9, 9, 9, 10, 11, 12, 12, 15.
9, 9, 9, 10, 11, 12 ,12.
9, 9, 10, 11, 12.
9, 10, 11.
10 is now our median since we inserted 12 into our list.
Your answer is 12.
I hope this helps!
Answer:
1,800$
Step-by-step explanation:
25% is 1/4th of the total amount. So...
Divide 2,400$ by 4 and get 600
Now, subtract 600 from 2,400.
Note:
Pls notify me if my answer is incorrect for the other users that will see this response. Thank you.
<em>-kiniwih426</em>
Answer:
Sorry, i dont know
Step-by-step explanation:
I dont know the answer to this question.....