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3 years ago

B) यदि 4,6, 9,11,107 k को मध्यक 8 भए यसको मध्यिका

Mathematics

1 answer:

Neporo4naja [7]3 years ago

8 0

Answer:

No clue, sorry, I need points

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Fie ∆ABC dreptunghic,m(unghiului B)=90°.Punctul M este mijlocul ipotenuzei.Stiind ca m(unghiului A)=30°si MC =3,2cm.Aflati perim

babymother [125]

Answer:

Step-by-step explanation:

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4 years ago

Trying to pass a test <br><br> (1/3)g+6=12

rodikova [14]

Answer:

g = 18

Step-by-step explanation:

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2 years ago

Two vertical poles of heights 60 ft and 80 ft stand on level ground, with their bases 100 ft apart. A cable that is stretched fr

Andreyy89

Answer:

Step-by-step explanation:

Given

height of two Poles are 60 and 80 ft

Distance between them is 100 ft

Let x be the distance of Pole of ht 80 ft from Point of stretch

thus length of rope is given by

$L=L_1+L_2$

$L_1=\sqrt{80^2+x^2}$

$L_2=\sqrt{60^2+(100-x)^2}$

$L=\sqrt{80^2+x^2}+\sqrt{60^2+(100-x)^2}$

differentiate w.r.t x we get

$\frac{\mathrm{d} L}{\mathrm{d} x}=\frac{2x}{2\sqrt{80^2+x^2}}-\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}$

Put $\frac{\mathrm{d} L}{\mathrm{d} x}=0$ to get minimum value

$\frac{2x}{2\sqrt{80^2+x^2}}=\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}$

squaring

$x^2\left ( (100-x)^2+60^2\right )=(100-x)^2(80^2+x^2)$

Rearranging

$28x^2-1800x+640000=0$

$x=\frac{400}{7}$

thus $L_1=98.312 ft$

$L_2=73.73 ft$

$L=172.04 ft$

7 0

3 years ago

Please help, I will give brainliest to whoever shows there work, and if it is right.

vitfil [10]

Your equation is presented in by the following formula of y = mx + b

m = slope, it is the coefficient of X

y = 4/5 X - 3

m = 4/5

5 0

4 years ago

What is 15 3/5 % in simplest form

cestrela7 [59]

15 3/5% = 15.6% = 0.156

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3 years ago