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galina1969 [7]
3 years ago
14

108 - 271 + 215-_____= -103

Mathematics
1 answer:
kupik [55]3 years ago
5 0
108-271+215-_____=-103
Im going to combine the first thee numbers and replace the blank with a variable, lets use x. 
52 - x=-103
now I am going to subtract 52 on both sides to get the variable alone
-x=-155
Im going to multiply both sides to eliminate the negitive in the variable
x=155
If you want to check just plug 155 into the blank
108-271+215-155=-103
-163+215-155=-103
52-155=-103
-103=-103

so after checking work the blank is equal to 155.


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Find derivative: ^6 square root x^5
SVEN [57.7K]

\large\begin{array}{l} \textsf{Find the derivative of}\\\\ \mathsf{f(x)=\,^6\!\!\!\sqrt{x^5}}\qquad\qquad\textsf{(expressing it as a power...)}\\\\ \mathsf{f(x)=x^{\frac{5}{6}}} \end{array}


\large\begin{array}{l} \textsf{So you can use the power rule to differentiate it:}\\\\ \mathsf{f'(x)=\big(x^{\frac{5}{6}}\big)'}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\,x^{\frac{5}{6}-1}}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\,x^{\frac{5}{6}-\frac{6}{6}}} \end{array}

\large\begin{array}{l} \mathsf{f'(x)=\dfrac{5}{6}\,x^{\frac{5-6}{6}}}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\,x^{-\,\frac{1}{6}}}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\cdot \dfrac{1}{x^{\frac{1}{6}}}}\\\\ \mathsf{f'(x)=\dfrac{5}{6x^{\frac{1}{6}}}}\\\\\\ \boxed{\begin{array}{c}\mathsf{f'(x)=\dfrac{5}{6\,^6\!\!\!\sqrt{x}}} \end{array}}\qquad\checkmark \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154186</span>


\large\textsf{I hope it helps. :-)}


Tags: <em>derivative sixth root irrational function power rule differential calculus</em>

3 0
3 years ago
What is the answer 1 - 0.5137
4vir4ik [10]

Answer:

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Step-by-step explanation:

6 0
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Step-by-step explanation:

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2 years ago
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8 0
3 years ago
2x - y = 10
Zolol [24]
You can plug -x - 1 for y in the first equation

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(3, -4)
7 0
3 years ago
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