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gizmo_the_mogwai [7]
3 years ago
9

The measures of the angles of a triangle are shown in the figure below. Solve for x.

Mathematics
2 answers:
Liula [17]3 years ago
3 0

Answer:

Step-by-step explanation:

x=180-59-41

x=80

lesya692 [45]3 years ago
3 0

Answer: 80°

Step-by-step explanation:

The sum of all angles in a triangle is always 180°

so 59° + 41° + x ° = 180°

or x = 180 - 41 - 59 = 80

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Tamara purchased 31 cases of tile to use on her bathroom floors .she used 17 cases in her upstairs bathroom and the rest in her
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8 less than the product of 6 and -16
Pachacha [2.7K]

Answer:

-104

Step-by-step explanation:

Step 1: Write out expression

6(-16) - 8

Step 2: Evaluate

-96 - 8

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3 0
3 years ago
Solve Tan^2x/2-2 cos x = 1 for 0 < or equal to theta < greater or equal to 1.
mixer [17]

Answer:

x = theta = 0°

Step-by-step explanation:

Given the trigonometry function

Tan²x/2-2 cos x = 1

Tan²x-4cosx = 2 ... 1

From trigonometry identity

Sec²x = tan²x+1

tan²x = sec²x-1 ... 2

Substituting 2 into 1, we have:

sec²x-1 -4cosx = 2

Note that secx = 1/cosx

1/cos²x - 1 - 4cosx = 2

Let cosx. = P

1/P² - 1 - 4P = 2

1-P²-4P³ = 2P²

4P³+2P²+P²-1 = 0

4P³+3P² = 1

P²(4P+3) = 1

P² = 1 and 4P+3 = 1

P = ±1 and P = -3/4

Since cosx = P

If P = 1

Cosx = 1

x = arccos1

x = 0°

If x = -1

cosx = -1

x = arccos(-1)

x = 180°

Since our angle must be between 0 and 1 therefore x = 0°

4 0
3 years ago
Solve the system of linear operations
zhenek [66]

Answer:

\boxed{(-2,1)}

Step-by-step explanation:

\left \{ {{5x+2y=-8} \atop {x+4y=2}} \right.

I'll be solving this system of equations using the elimination method since the x and y values are neatly lined up.

I want to get a pair of x's or y's that cancel out, and it looks like the easiest way to start would be by multiplying the first equation by -2 (the y's will cancel).

I chose to multiply the first equation by -2 instead of multiplying the second equation by 5 because -2 is a smaller number and easier to multiply by.

-2\times(5x+2y=-8)

Distribute -2 inside the parentheses. Now you've got:

\left \{ {{-10x-4y=16} \atop {x+4y=2}} \right.

Add up the equations from top to bottom.

-10x plus x is -9x, the -4y and 4y cancel out, and 16 plus 2 is 18. Make this one single equation.

-9x=18

Divide both sides by -9.

x=-2

Substitute this value of x into the second equation (less to do with the x since it has no coefficient which means no multiplying).

(-2)+4y=2

Add 2 to both sides.

4y=4

Divide both sides by 4.

y=1

The final answer is x=-2, ~y=1.

7 0
3 years ago
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