d = 3 , a₁₂ = 40 and S = 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a
= a₁ + (n-1)d</h3><h3>• S
=
[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =
[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
Answer:
Plane R
Plane DEG
Plane FDG
Plane FEG
Step-by-step explanation:
You can name the plane by the script letter "R", and you can name the plane with any three co-linear points on the plane
Answer:
5%
Step-by-step explanation:
Solve for p by simplifying both sides of the equation, then isolating the variable
Basically, you plug in -4 for x and -7 for y (since -4 is the x coordinate and -7 is the y coordinate). When doing that, you get:
-14=-16+2
-8+7=-1
im not gonna say the answer, but looking at these equations, you can probably tell if they work or not :)
It would be great if you attached the spreadsheet