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torisob [31]
3 years ago
12

Differentiate with respect to x (and simplify): 2x(1-x)^3 I need to show working out. I will mark the best answer BRAINLIEST

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

First of all expand the terms

2x(1-x)³ = 2x( 1 - 3x + 3x² - x³)

Multiply by 2x

You will get

2x - 6x² + 6x³ -2x⁴

Differentiate each of the terms using differentiation rules

You will get

2 - 12x + 18x² - 8x³

So the final answer is

- 8x³ + 18x² - 12x + 2

Hope this helps.

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The table gives a partial set of values of a polynomial h(x), which has a leading coefficient of 1. x –2 0 1 2 3 h(x) 0 –12 0 8
weqwewe [10]

Using the Factor Theorem, the equation of h(x) is given as follows:

h(x) = -2(x³ - 2x² - 5x + 6)

<h3>What is the Factor Theorem?</h3>

The Factor Theorem states that a polynomial function with roots x_1, x_2, \codts, x_n is given by:

f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)

In which a is the leading coefficient.

Looking at the table, considering the values of x when h(x) = 0, the roots of h(x) are given as follows:

x_1 = -2, x_2 = 1, x_3 = 3

Then the rule is:

h(x) = a(x + 2)(x - 1)(x - 3)

h(x) = a(x² + x - 2)(x - 3)

h(x) = a(x³ - 2x² - 5x + 6)

The h-intercept is of -12, as when x = 0, h = -12, hence this is used to find a as follows:

6a = -12

a = -12/6

a = -2.

Hence the function is given by:

h(x) = -2(x³ - 2x² - 5x + 6)

More can be learned about the Factor Theorem at brainly.com/question/24380382

#SPJ1

8 0
2 years ago
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