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CaHeK987 [17]
3 years ago
10

Helpppp plsssss Asap!!!​

Mathematics
1 answer:
RideAnS [48]3 years ago
8 0

What is your question?

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What is the slope of the line in the graph shown above?
erastova [34]
Use the 2 points and use the formula
\frac{y2 - y1}{x2 - x1}
to get slope
\frac{3 - 1}{0 - 1}
and you get a slope of -2
for the second question its non of the above? i think the x intercept is 0.6666. if you're talking about y intercept then its -5
4 0
4 years ago
Read 2 more answers
What is the equation of a line that is perpendicular to -x + 2y =4 and passes through the point (-2, 1)
Trava [24]

Answer:

y = -2x - 3

Step-by-step explanation:

-solve for y: y = 1/2x + 2

-perpendicular equals opposite slope: -2

-plug in the point: (1) = -2(-2) + b

                               1 = 4 + b

                                b = -3

put it all together: y = -2x - 3

8 0
3 years ago
Kiera is cleaning her neighbors garage. She is being paid a $25 flat fee and $8 per hour for each hour that she works. Kiera mak
Aloiza [94]

Answer:

She worked 7 hours..........

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
"If three angles and two sides of two triangles are congruent, are the triangles congruent? Why or why not?"
Anettt [7]

Answer:

yes

Step-by-step explanation:

because the corresponding angles are congruent, the triangles are congruent through CPCTC. If two sides are congruent and an included angle, then the triangles are congruent through the SAS postulate. And if two sides and a non-included angle are congruent then the triangles are congruent through the AAS postulate. Any way of looking at this proves congruency through various postulates, therefore the trianlges are congruent.

3 0
3 years ago
What are all of the real roots of the following polynomial? f(x) = x^4 -24x^2 - 25 A. -1 or 1 B. -5 or 5 C. -5, -1, 1, or 5 D. -
professor190 [17]

For this case we have the following function:

f (x) = x ^ 4-24x ^ 2-25

We make a change of variable:

u = x ^ 2

So, we have:

u ^ 2-24u-25

We apply the resolver:

a = 1\\b = -24\\c = -25\\

u = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\u = \frac {- (- 24) \pm \sqrt {(- 24) ^ 2-4 (1) (- 25)}} {2 (1)}\\u = \frac {24 \pm \sqrt {576 + 100}} {2}\\u = \frac {24 \pm \sqrt {676}} {2}\\u = \frac {24\pm26} {2}

We have two roots:

u_ {1} = \frac {24 + 26} {2} = 25\\u_ {2} = \frac {24-26} {2} = - 1

Returning the change:

x ^ 2 = 25\\x = \pm \sqrt {25} = \pm5

x ^ 2 = -1 Give the imaginary roots.

Answer:

Real roots \pm5

5 0
3 years ago
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