<em>1</em><em> </em><em>I </em><em>do </em><em>not </em><em>know</em>
<em>2</em><em> </em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>is </em><em>so </em><em>hard</em>
<em>3</em><em> </em><em>i</em><em> </em><em>don't </em><em>know</em><em> </em><em>what</em><em> </em><em>is </em><em>the </em><em>answer</em><em />
In one day, there are 24 hours. In 1 hour, there are 3,600 seconds. So, that means that there are 86,400 seconds. Also, in 1 day, the short hand which denotes the number of hours, makes 2 revolutions around the clock. Its distance traveled would be twice the perimeter of the circle.
Distance traveled by hour hand = 2(2πr) = 4πr₁
In 60 s, the long hand, which denotes numbers of minutes, makes one revolution around the clock. Since there are 86,400 seconds in a day, that would be a total of 1,440 revolutions.
Distance traveled by minute hand = 1,440(2πr) = 2,880πr₂
Difference = 2880πr₂ - 4πr₁ = 4π(720r₂ - r₁), where r₁ is the length of hour hand and r₂ is the length of minute hand.
Answer:
the amount after 5 years using compound continuously is $135.03
Step-by-step explanation:
The computation of the amount after 5 years using compound continuously is as follows
= Principal × e^(rate × time period)
= $110 × e^(4.2% × 5)
= $110 × 1.227525065
= $135.03
Hence, the amount after 5 years using compound continuously is $135.03
We simply applied the above formula so that the correct value could come
And, the same is to be considered
Answer:
The area of the shaded portion of the figure is 
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The shaded area is equal to the area of the square less the area not shaded.
There are 4 "not shaded" regions.
step 1
Find the area of square ABCD
The area of square is equal to
where
b is the length side of the square
we have
substitute
step 2
We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):
The area of circle is equal to
The diameter of the circle is equal to the length side of the square
so
---> radius is half the diameter
substitute
Therefore, the area of 2 "not-shaded" regions is:
and the area of 4 "not-shaded" regions is:
step 3
Find the area of the shaded region
Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:
so
---> exact value
assume
substitute
