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2 years ago

Find the product. -mnp(3m - 5n 7p)

2 answers:

5 0

If you would like to find the product, you can calculate this using the following steps:

-mnp * (3m - 5n7p) = -mnp * 3m + mnp * 5n7p = -3m^2np + 35mn^2p^2

The correct result would be -3m^2np + 35mn^2p^2.

Nataliya [291]2 years ago

3 0

$-mnp(3m-5n7p)=\\\\-mnp\times3m+mnp\times5n7p=\\\\-3m^2np+35mn^2p^2\\\\\sf\ ANSWER={\boxed{-3m^2np+35mn^2p^2}$

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Given that x/1 = 3y/8, find the ratio of : y

brilliants [131]

Answer:

3 : 8

Step-by-step explanation:

$\frac{x}{1} = \frac{3y}{8}$

cross multiply

8x = 3y

x = 3/8

x : y = 3 : 8

5 0

3 years ago

Solve the equation 905=5a

Annette [7]

905=5a

905/5=5a/5

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2 years ago

Read 2 more answers

Identify the cross section of the solid shown in the diagram

Ivahew [28]

Given:

Image of the pyramid

To identify:

The cross section of the solid.

Solution:

The given image is a pyramid.

The base of the pyramid have 5 edges.

So, it is a pentagonal pyramid.

In the cross section also have 5 edges.

Therefore the cross section of the solid shown in the diagram is pentagon.

6 0

3 years ago

Determine the next step for solving the quadratic equation by completing the square.

Studentka2010 [4]

Answer:

The solutions are $x=\frac{1+\sqrt{7}}{2}$ and $x=\frac{1-\sqrt{7}}{2}$

Step-by-step explanation:

we have

$0=-2x^{2}+2x+3$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$-3=-2x^{2}+2x$

Factor the leading coefficient

$-3=-2(x^{2}-x)$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$-3-0.5=-2(x^{2}-x+0.5^{2})$

$-3.5=-2(x^{2}-x+0.5^{2})$

Rewrite as perfect squares

$-3.5=-2(x-0.5)^{2}$

$7/4=(x-0.5)^{2}$

square root both sides

$x-0.5=(+/-)\sqrt{\frac{7}{4}}$

$x-\frac{1}{2}=(+/-)\frac{\sqrt{7}}{2}$

$x=\frac{1}{2}(+/-)\frac{\sqrt{7}}{2}$

$x=\frac{1+\sqrt{7}}{2}$

$x=\frac{1-\sqrt{7}}{2}$

4 0

3 years ago

solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars

Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

Every x has only one value of y

x appears once in ordered pairs

<u><em>Examples:</em></u>

The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)

The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)

The domain is the set of values of x

The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0

2 years ago