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3 years ago

7

I need help on question 35

1 answer:

Novay_Z [31]3 years ago

5 0

Pretty sure it's everything except irrational

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How do I solve the equation 6=-w/8

MrRa [10]

Answer:

-48

Step-by-step explanation:

Multiply both sides of the equation by -8

-8(6) = $\frac{-w}{8}$ (-8)

-48 = w

4 0

2 years ago

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What is the sum of two rational numbers?

ZanzabumX [31]

A rational answer 2 + 2 = 4

3 0

3 years ago

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Lapatulllka [165]

I think it’s A.6.3
Sorry if I’m wrong but I’m pretty sure it’s that.

7 0

4 years ago

PLEASE HELP ME OUT please i don’t understand

Anvisha [2.4K]

Answer: 228.01 pi and the second is near 715. 9514

Step-by-step explanation: area of a circle is pi times the radius squared. Radius is half a diameter. Half of 30.2 is 15.1. 15.1 squared is 228.01. If you use 3.14 in place of pi, and multiply that to 228.01 you get 715.9514. I think

8 0

3 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

3 years ago