1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DerKrebs [107]
2 years ago
14

21 18 15 12 9 6 3 1 2 3 4 5 6 7

Mathematics
2 answers:
PtichkaEL [24]2 years ago
8 0
Sorry what what is the question?
Marianna [84]2 years ago
4 0

Answer:

What is the question?

Step-by-step explanation:

You might be interested in
PLEASE HELPPPPPPPPP!!!!?????
natta225 [31]

Answers:

  • Mean = 69
  • Median = 69
  • Mode = {68, 70}

===============================================

Explanations:

To get the mean, you add up all of the values and then you divide by N, where N is the number of values in the list. In this case, you'll divide by N = 8.

Adding up all the values gets you 70+68+70+72+68+66+65+73 = 552. Dividing that over 8 then leads to the arithmetic mean of 552/8 = 69

-------

To find the median, you'll first sort the values from smallest to largest. You should have this set {65, 66, 68, 68, 70, 70, 72, 73} after sorting. Next, cross off the smallest and largest values to end up with this smaller set {66, 68, 68, 70, 70, 72}. We do this so we can locate the middle-most item.

Repeat the process of crossing off the smallest and largest items to get {68, 68, 70, 70}. Do so one more time and we get {68,70}.

The midpoint of those two values is (68+70)/2 = 138/2 = 69. The median is 69. The mean and median may not always be the same value.

--------

The mode is the most frequent value. In this case, we have 68 and 70 show up exactly twice for each unique value. This is the most compared to the other unique values that only show up exactly once.

It is possible to have more than one mode, as long those values are more frequent than the rest. We denote the mode as a set, so the mode is {68, 70}

8 0
2 years ago
Beth poured the same amount of juice into 1010 glasses. She used 22 quarts of juice. How much juice is in each glass?
lozanna [386]
22qt/1010gl=11/505 qt/glass
6 0
3 years ago
Draw to explain how these to problems are different 35-15 and 43-26
Burka [1]
Well, 
35 - 15 = 20
43 - 26 = 17
The difference is that there 3 apart ( I just subtracted 20 with 17 and got 3)
Hope This Helps!!!
:)
4 0
3 years ago
Read 2 more answers
Two communications companies offer calling plans. With Company X, it costs 30¢ to connect and
sesenic [268]

Answer:

D

Step-by-step explanation:

      you can model the amount that each phone plan will cost after n    minutes with these linear equations

                company X: 30 + 5n

                company Y: 20 + 4n

if you subtract the functions you can get the function for the

30 + 5n - ( 20 + 4n )

7 0
3 years ago
Help I cant figure out how to do this type of problem
Dafna1 [17]
It’s going to be north in the east
7 0
2 years ago
Other questions:
  • 2) On average, 75% of the planes leave on time. If 120 planes left on time
    10·1 answer
  • A coach is assessing the correlation between the number of hours spent practicing and the average number of points scored in a g
    8·1 answer
  • Please help!I will make brainliest
    5·2 answers
  • The order of several matrices are given. A = 3x2 B = 3x5 C = 2x3 D = 5x7 E = 3x5 Which can be multiplied?
    13·1 answer
  • Simplify.<br><br> x + (7 + 14x)<br><br> 15 x + 7<br> 21 x<br> 22 x<br> 21 x + 1
    9·1 answer
  • A bike path crosses a road as shown. Solve for each indicated angle measure or variable.
    9·1 answer
  • I NEED HELP WITH THIS!
    15·1 answer
  • When creating equivalent fractions (creating common denominators) you only need to change the denominators.
    13·1 answer
  • 5×70=5×(_×10)<br>5×70=(5×_)x10<br>5×70=_×10=_​
    9·1 answer
  • I already know the answer I just need someone to explain step by step how to solve it. I need to know the process ​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!