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3 years ago

What is the equation of the line that passes through point (4, 12) and has a intercept of -2

Mathematics

1 answer:

kozerog [31]3 years ago

7 0

Answer:

$\large\boxed{y=\dfrac{7}{2}x-2}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the point (4, 12), and y-intercept b = -2 → (0, -2).

Substitute:

$m=\dfrac{-2-12}{0-4}=\dfrac{-14}{-4}=\dfrac{14:2}{4:2}=\dfrac{7}{2}$

Finally:

$y=\dfrac{7}{2}x-2$

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What is the equation of the line that passes through point (4, 12) and has a intercept of -2​

What is the equation of the line that passes through point (4, 12) and has a intercept of -2