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olga_2 [115]
4 years ago
6

What is the absolute value of 1 -32 1

Mathematics
2 answers:
zheka24 [161]4 years ago
6 0

Answer:

If you mean |-32 | , then the answer is 32.

zmey [24]4 years ago
4 0
The answer is 32 ... xx
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Need help asap!!!! What’s the answer to this?? Having any answers
Dennis_Churaev [7]

Hello.

One jug contains

650 millilitres of water.

The other jug contains

300 millilitres of oil.

In order to find how much more water there is than oil, we need to take the amount of oil and subtract it from the amount of water:

\mathrm{650-300}

\mathrm{350}

Therefore, there are 350 more millilitres of water than oil.

I hope it helps.

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\boxed{imperturbability}

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2 years ago
Please help with this problem . Break it down for me 15-1/6n=1/6n-1
Lisa [10]
15-1/6n=1/6n-1
First, lets multiply both sides by 6 so that n is a whole number:
90-n=n-6
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3 0
3 years ago
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If you can buy 1⁄3 of a box of chocolates for 6 dollars, how much can you purchase for 4 dollars? Write your answer as a fractio
Stella [2.4K]
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Choose the graph which represents the solution to the inequality:<br> 3x + 8 ≥ 11
Ede4ka [16]

Answer:

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Step-by-step explanation:

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Best regards

4 0
3 years ago
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Solving systems of equations using any method
andreev551 [17]

Answer:

x = 5 , y = 2

Step-by-step explanation:

Solve the following system:

{y = (7 x)/5 - 5 | (equation 1)

{y = (3 x)/5 - 1 | (equation 2)

Express the system in standard form:

{-(7 x)/5 + y = -5 | (equation 1)

{-(3 x)/5 + y = -1 | (equation 2)

Subtract 3/7 × (equation 1) from equation 2:

{-(7 x)/5 + y = -5 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 1 by 5:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 2 by 7/4:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+y = 2 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(7 x)+0 y = -35 | (equation 1)

{0 x+y = 2 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 5 | (equation 1)

{0 x+y = 2 | (equation 2)

Collect results:

Answer:  {x = 5 , y = 2

7 0
4 years ago
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