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Scorpion4ik [409]
3 years ago
8

A drug company claims that fewer than 1% of pills that it produces and ships fail to retain full potency after 60 days of produc

tion.
An inspector inspects a shipment of medications to determine the efficacy in terms of the proportion p in the shipment that failed to retain full potency after 60 days of production. To do so, she selects an SRS of 200 pills. Suppose that eight of the 200 pills have failed to retain their full potency.

The test statistic for the proportion of pills that have failed to retain their potency is...
(Round your answer to two decimal places)
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
8 0
4% of the 200 pills failed to retain full potency after 60 days.
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The weight, in pounds, of a newborn baby t months after birth can be modeled by the equation W=1.5t+10. What is the slope of the
Daniel [21]

Answer:

Step-by-step explanation:

W = 1.5t + 10

slope = 1.5

Every month, the baby gains 1.5 pounds.

6 0
3 years ago
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Luis wants to buy a skateboard that usually sells for $79.97. All merchandise is discounted by 12%. What is the total cost of th
Tju [1.3M]

Answer:

$74.8

Step-by-step explanation:

step 1: apply the discount to the price

12% = .12

$79.97 X .12 = $9.5964

$79.97 - $9.5964 = $70.3736

step 2: apply tax

$70.3736 X .0625 = $4.39835

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step3: round

$74.8

5 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
amm1812

Answer:

6546 students would need to be sampled.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.

This means that n = 200, \pi = \frac{118}{200} = 0.59

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?

n students would need to be sampled, and n is found when M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.645\sqrt{\frac{0.59*0.41}{n}}

0.01\sqrt{n} = 1.645\sqrt{0.59*0.41}

\sqrt{n} = \frac{1.645\sqrt{0.59*0.41}}{0.01}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.59*0.41}}{0.01})^2

n = 6545.9

Rounding up:

6546 students would need to be sampled.

3 0
3 years ago
The sum of two numbers is 42, and one of the numbers is 5 times the other. Find the two numbers.
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5x+x=42
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