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2 years ago

Luke earns $11.00 per hour. He works 32 1/2 hours per week. What is his weekly wage

Mathematics

2 answers:

ira [324]2 years ago

8 0

Answer: 357.50

Step-by-step explanation:

Multiply 11.0 and 32.5 without the decimal points.

It should look like this: 110 × 325

After you solve this equation, count the numbers after the decimal points in 11.0 and 32.5. There is one number after the decimal point in 11.0, and one number after the decimal point in 32.5. In the number 35750, count from the last number and add a decimal point right before the 5.

Hope it helps!!

skad [1K]2 years ago

6 0

Luke’s weekly wage would be $357.5 because you multiply the 11 dollars an hour times the hours a week

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Replace x with the x values.

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5 0

1 year ago

Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

Simplify,

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

$\frac{5(+-)\sqrt{25-8}}{4}$

$\frac{5(+-)\sqrt{17}}{4}$

Rewrite,

$\frac{5(+-)\sqrt{17}}{4}$

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

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2 years ago