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emmasim [6.3K]
3 years ago
7

PLEASE SOMEONE HELP ME MY LIFE LITERALLY DEPENDS ON IT I WILL PAY IF NEEDED PLEASE I WILL DIE

Mathematics
1 answer:
Orlov [11]3 years ago
3 0
X + Y > 4
16x + 5y < 75

Each one of those inequality signs should be "or equal to," so be sure to write that in your final answer. X represents live bait, which is $16 per pound, and Y represents natural bait, which is $5 per pound. X + Y > 4lb, because John stated he wanted at least 4lb of bait. Therefore, the pounds of natural bait purchased plus the pounds of live purchased must be greater than or equal to 4lb. Since we are told John's budget is $75, the amount of money spent on both natural and live bait must be less or equal to $75. Therefore, we can write an inequality to express that as 16x + 5y < 75. Hope this helps!
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Which expression is equivalent to (4 + 6)²?
mel-nik [20]

Answer:

A) -20+48i

Step-by-step explanation:

(4+6i)^2\\(4+6i)(4+6i)\\16+24i+24i+36i^2\\**i^2=-1*\\16+48i+36i^2(-1)\\16+48i-36\\-20+48i

5 0
1 year ago
The formula for the cost of buying a car=
svet-max [94.6K]
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5 0
3 years ago
The force on an area 16 m by 12 m is 24,000 N. What is the pressure per square meter?
Dmitrij [34]
Recall that 
Pressure = Force ÷ Area

In this context we have,
Pressure = 24,000 ÷ (16 × 12)
               = 24,000 ÷ 192
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6 0
3 years ago
Read 2 more answers
A study of 12,000 able-bodied male students at the University of Illinois found that their times for the mile run were approxima
den301095 [7]

Answer:

P (y < 6) = \frac{P(y- \mu)}{\sigma}  \mu}{\sigma} \\\\=P(z

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618

Step-by-step explanation:

Normal with mean 6.88 minutes and

a standard deviation of 0.57 minutes.

Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)

\mu = 6.88

\sigma = 0.57

y ≈ normal (μ, σ)

The z score is the value decreased by the mean divided by the standard deviation

P (y < 6) = \frac{P(y- \mu)}{\sigma}  \mu}{\sigma} \\\\=P(z

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618

3 0
3 years ago
WILL GIVE BRAINLIEST!!!
Mnenie [13.5K]
The answer to your question is 34.13%
8 0
3 years ago
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